Question

我正在尝试使用jQuery show / hide来控制div的显示，具体取决于是否选中了复选框。（我也尝试过使用display none / block的CSS方法。）

我可以使用代码来检查复选框然后让div显示或隐藏，但是，我无法检查所有＆＃34;检查所有＆＃34;按钮也可以起作用，如果选中了特定复选框，则相应地显示/隐藏div。

我把它放到JSFiddle中：https://jsfiddle.net/gamehendgeVA/2jszhdzw/

有人可以帮我把单选中的复选框显示/隐藏与＆＃34;检查全部＆＃34;根据要检查的特定复选框显示和隐藏div的按钮？

感谢您的帮助！

HTML

<div class="panel panel-info">
<div class="panel-heading"><h3 class="panel-title">Search These Domains</h3></div>
<div class="panel-body">
<input type="button" class="btn btn-primary btn-xs" data-toggle="button" value="all domains" id="checkAllDomains" />
<br />
<div class="col-md-6">
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox" id="domainCheckbox1">One</label></div>
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox">Two</label></div>
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox">Three</label></div>
</div>
<div class="col-md-6">
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox">Four</label></div>
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox">Five</label></div>
<div class="checkbox"><label><input type="checkbox" class="searchDomainCheckbox">Six</label></div>
</div>
</div> <!-- /.panel-body -->
</div> <!-- /.panel -->
<div class="panel panel-info" id="div1">
<div class="panel-heading"><h3 class="panel-title">Search These Divisions</h3></div>
<div class="panel-body">
THIS DIV SHOULD ONLY APPEAR WHEN "#domainCheckbox1" is checked, either when checked on its own, or checked when the "all domains" button checks it.
</div> <!-- /.panel-body -->
</div> <!-- /.panel -->

JS

$('#div1').hide();
$('#domainCheckbox1').change(function(){
  if($(this).prop("checked")) {
    $('#div1').show();
  } else {
    $('#div1').hide();
   }
});
/////////
$(function() {
    function updateCheckAllButtonDomains() {
        if ($('.searchDomainCheckbox:checked').length == $('.searchDomainCheckbox').length) {
        $('#checkAllDomains').val('uncheck all').data('check', false);
    } else {
        $('#checkAllDomains').val('all domains').data('check', true);
    }       
}
$('.searchDomainCheckbox').change(function() {
    updateCheckAllButtonDomains();
});
$('#checkAllDomains').click(function() {
    $('.searchDomainCheckbox').prop('checked', $(this).data('check'));
    updateCheckAllButtonDomains();
});
updateCheckAllButtonDomains();
});

Answer 1

Demo

只需触发Change事件就可以了

function updateCheckAllButtonDomains() 
{
    if ($('.searchDomainCheckbox:checked').length == $('.searchDomainCheckbox').length)
        $('#checkAllDomains').val('uncheck all').data('check', false);
    else 
        $('#checkAllDomains').val('all domains').data('check', true);

    $("input.searchDomainCheckbox").trigger("change");
}

Answer 2

这是因为searchDomainCheckbox事件已经附加到元素上。因此，您必须手动触发，如下所示：$('.searchDomainCheckbox').trigger('change');

将此代码放在#checkAllDomains的事件点击上并快乐！

这是我的解决方案：

$('#checkAllDomains').click(function() {
    $('.searchDomainCheckbox').prop('checked', $(this).data('check'));
    $('.searchDomainCheckbox').trigger('change');
    updateCheckAllButtonDomains();
});

注意：将触发器置于updateCheckAllButtonDomains（）内部会导致＆＃34;超出最大调用堆栈大小＆＃34; 。

Answer 3

以下是jsFiddle

HTML

<div class="panel panel-info">
<div class="panel-heading">
    <h3 class="panel-title">Search These Domains</h3>
</div>
<div class="panel-body">
    <input type="checkbox" id="checkAllDomains" />
    <label>Check All</label>
    <br />
    <div class="col-md-6">
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">One</label>
        </div>
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">Two</label>
        </div>
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">Three</label>
        </div>
    </div>
    <div class="col-md-6">
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">Four</label>
        </div>
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">Five</label>
        </div>
        <div class="checkbox">
            <label>
                <input type="checkbox" class="searchDomainCheckbox">Six</label>
        </div>
    </div>
</div>
<!-- /.panel-body -->

JAVASCRIPT

$('#checkAllDomains').click(function (event) {
    if (this.checked) {
        $('.searchDomainCheckbox').each(function () {
            this.checked = true;
        });
    } else {
        $('.searchDomainCheckbox').each(function () {
            this.checked = false;
        });
    }
});

jquery复选框show hide div不工作

3 个答案: