Question

我有以下查询

SELECT      distinct DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0) as Date
FROM         [Vente A]

union 

SELECT      distinct DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
FROM         [Vente B]

UNION 

SELECT      distinct DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
FROM           [Budget B]

UNION 

SELECT      distinct DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
FROM            [Budget A]

我需要选择Vente A和Vente B的日期然后选择预算A和预算B中的选项，其中日期小于Vente A和Vente B的最大日期

我该怎么做？

Answer 1

我假设你想要这个：从联合od Vente A和B中选择最大日期。然后显示预算A和B联合的所有行，其中数据小于上面选择的最大日期。

SELECT BudgetDate
FROM (
  SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0) AS BudgetDate
  FROM [Budget B]

  UNION

  SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
  FROM [Budget A]
  ) BudgetAB
WHERE BudgetDate < (
    SELECT MAX(DATE)
    FROM (
      SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0) AS DATE
      FROM [Vente A]

      UNION

      SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
      FROM [Vente B]
      ) AS VenteAB
    )

或者，像这样

;WITH BudgetAB
AS (
  SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0) AS BudgetDate
  FROM [Budget B]

  UNION

  SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
  FROM [Budget A]
  )
SELECT BudgetDate
FROM BudgetAB
WHERE BudgetDate < (
    SELECT MAX(DATE)
    FROM (
      SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0) AS DATE
      FROM [Vente A]

      UNION

      SELECT DISTINCT DATEADD(hour, DATEDIFF(hour, 0, [Date Time]), 0)
      FROM [Vente B]
      ) VenteAB
    )

使用sql server修改查询

1 个答案: