打印链表卡在无限循环中[关闭]

时间:2015-10-24 17:55:58

标签: java class linked-list nodes

如果您帮助我解决下一个问题,我将不胜感激。所以我创建了Item类的对象并将其放在链表中。当我尝试从函数“itemCost”打印列表时,它始终以无限循环打印第一个对象的内容。

主要 -

import java.util.*;

public class Main {
    static Scanner reader = new Scanner(System.in);

    public static void main(String[] args) {
        String name;
        double price;
        int id, amount;
        Item s;
        Node<Item> a = null, p = null, tmp = null;
        System.out.println("Enter number of items: ");
        int n = reader.nextInt();
        for (int i = 0; i < n; i++) {
            System.out.println("Enter id: ");
            id = reader.nextInt();
            System.out.println("Enter name: ");
            name = reader.next();
            System.out.println("Enter price: ");
            price = reader.nextDouble();
            System.out.println("Enter amount: ");
            amount = reader.nextInt();
            s = new Item(id, name, amount, price);
            tmp = new Node<Item>(s);
            if (a == null) {
                a = tmp;
                p = tmp;
            } else {
                a.setNext(tmp);
                p = tmp;
            }
        }
        itemCost(a);
    }

    // This is the problem. It's print in infinite loop the first Item only
    // instead all of the items in the list
    public static void itemCost(Node<Item> s) {
        Node<Item> p = s;
        while (p != null) {
            System.out.println(p.toString());
            System.out.println("Total: " + p.getValue().getTotal());
            s.getNext();
        }
    }
}
  • 我不知道是否要添加Node或Item类所以如果你需要它们也请写信给我,我会补充。感谢

1 个答案:

答案 0 :(得分:0)

你的while循环永远不会改变它在条件中检查的变量,所以它永远不会终止。

尝试:

public static void itemCost(Node<Item> s){
  Node<Item> p = s;
  while(p != null){
      System.out.println(p.toString());
      System.out.println("Total: "+p.getValue().getTotal());
      p = p.getNext();
  }
}