我想提交另一个网站的表格&想得到回应。但是无法理解如何做到这一点。谁能帮帮我吗 ?
我的目标网站:http://xyz.php
我的代码:
var http = require('http');
var options = {
host: 'xyz.com',
path: '/xyz.php?textSearch=234567'
};
callback = function(response) {
var str = '';
response.on('data', function (chunk) {
str += chunk;
});
response.on('end', function () {
console.log(str);
});
}
http.request(options, callback).end();
答案 0 :(得分:1)
您应该使用POST请求,因为表单标记包含方法属性
<form id="frmThis" name="frmThis" method="post" action="">
试试这段代码:
var querystring = require('querystring');
var http = require('http');
var post_data = querystring.stringify({
txtSearch: "17051017387"
})
var options = {
host: 'nbr.gov.bd',
path: '/getbinfield.php',
method: 'POST',
headers: {
'Content-Type': 'application/x-www-form-urlencoded',
'Content-Length': post_data.length
}
};
callback = function(response) {
console.log(arguments);
var str = '';
response.on('data', function (chunk) {
str += chunk;
});
response.on('end', function () {
console.log(str);
});
}
var req = http.request(options, callback)
req.write(post_data)
req.end()
答案 1 :(得分:0)
使用request模块:
var request = require('request')
request.post('http://nbr.gov.bd/getbinfield.php', {
form: {
txtSearch: '...search for something',
bthSubmit: 'Search'
}
}, function (err, res, body) {
console.log(body)
})