Question

我遇到了一个奇怪的错误，我收到了数据库表的复数版本的消息，并且它被分组到我的续集查询中。我扫描了我的模型和路线，但找不到我的表名复数的任何实例，当我检查数据库表时，结构没有提到任何复数。当我记录查询时，看起来复数错误出现在查询的这一部分

FROM images AS images LEFT OUTER JOIN descriptions AS description ON

以下是完整的错误消息：

Unhandled rejection SequelizeDatabaseError: ER_NO_SUCH_TABLE: Table 'assistant.descriptions' doesn't exist

这是我的Images模型：

module.exports = function（sequelize，DataTypes）{

var Images = sequelize.define('images', {
    pattern: DataTypes.STRING,
    color: DataTypes.STRING,
    imageUrl: DataTypes.STRING,
    imageSource: DataTypes.STRING,
    description_id: DataTypes.INTEGER
}, {
    classMethods: {
        associate: function(db) {
            Images.belongsTo(db.Description, {foreignKey: 'description_id'});
        }
    }
});
    return Images;
}

这是我的Description模型： module.exports = function（sequelize，DataTypes）{

var Description = sequelize.define('description', {
    description_id: {
        type: DataTypes.INTEGER,
        primaryKey: true
    },
    color: DataTypes.STRING,
    body: DataTypes.STRING
});
    return Description;
}

以下是我如何关联dbIndex中的模型：

var Sequelize      = require('sequelize');
var sequelize = new Sequelize("assistant", "admin", "pwd", {
    host: "host",
    port: 3306,
    dialect: 'mysql'
});
var db = {};

db.Description = sequelize.import(__dirname + "/descriptionModel");

db.Images = sequelize.import(__dirname + "/imagesModel");

db.Images.associate(db);

db.sequelize = sequelize;
db.Sequelize = Sequelize;

module.exports = db;

这是我的问题：

router.get('/:pattern/:color/result', function(req, res, image){

    console.log(req.params.color);
    console.log(req.params.pattern);

    db.Images.findAll({ 
        where: {
            pattern: req.params.pattern,
            color: req.params.color
        },
        include: [db.Description],
        attributes: ['id', 'pattern', 'color', 'imageUrl', 'imageSource', 'description_id']
    }).then(function(image){
        //console.log(doc.descriptions_id);
        res.render('pages/suit-result.hbs', {
            pattern : req.params.pattern,
            color : req.params.color,
            image : image
            })
        });
});

以下是错误之前的查询：

Executing (default): SELECT `images`.`id`, `images`.`pattern`, `images`.`color`, `images`.`imageUrl`, `images`.`imageSource`, `images`.`description_id`, `description`.`description_id` AS `description.description_id`, `description`.`color` AS `description.color`, `description`.`body` AS `description.body`, `description`.`createdAt` AS `description.createdAt`, `description`.`updatedAt` AS `description.updatedAt` FROM `images` AS `images` LEFT OUTER JOIN `descriptions` AS `description` ON `images`.`description_id` = `description`.`description_id` WHERE `images`.`pattern` = 'solid' AND `images`.`color` = 'navy-blue';

Answer 1

默认情况下，Seqeulize会复数表名。要将其关闭，请在您不想要复数的所有模型定义选项中加入freezeTableName: true选项。例如，使用Description模型：

var Description = sequelize.define('description', {
  description_id: {
    type: DataTypes.INTEGER,
    primaryKey: true
  },
  color: DataTypes.STRING,
  body: DataTypes.STRING
}, {
  freezeTableName: true
});

Sequelize - 表多元化错误，表中没有实例

1 个答案: