Question

请帮我明星学习django。我试着理解为什么我得到404错误。

有我的主要urls.py

from django.conf.urls import include, url
from django.contrib import admin
admin.autodiscover()

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^/', include('account_app.urls')),
]

我的帐户urls.py 来自django.conf.urls导入模式，url

from account_app import views

urlpatterns = [
    url(r'^$', views.index, name='index')
]

有我对accout的看法

from django.shortcuts import render
from django.http import HttpResponse
from django.template import RequestContext, loader

from yes_no.models import account_class # added to model yes_no


def index(request):
    template = loader.get_template('./index.html')
    context = RequestContext(request, {
        'a' : a,
    })
    return HttpResponse(template.render(context))

P.S。我的index.html文件存在于accout view和urls file

的文件夹中

感谢您的帮助。

Answer 1

也许您需要开始使用Class Based View？一切都变得更加轻松。

urls.py应该是这样的

from django.conf import settings
from django.views.static import serve
from some_app.views import HomePageView(

urlpatterns = [
    url(r'^about/', HomePageView(.as_view()),
]

if settings.DEBUG:
    urlpatterns += [
        url(r'^media/(?P<path>.*)$', serve, {
            'document_root': settings.MEDIA_ROOT,
        }),
   ]

views.py

from django.views.generic.base import TemplateView

class HomePageView(TemplateView):
    template_name = "home.html"
    def get(self, request, *args, **kwargs):
        context = dict()
        context['foo'] = 'bar'
        return Homepage.render_to_response(self, context)

我们需要完整的跟踪错误

django的第一个项目

1 个答案: