Question

我必须用Python编写一个程序，提示用户输入一个文本，然后用嵌套循环将该文本与ASCII字符串（所有ASCII字符）进行比较。

ascii_string= """!"#$%&\'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~"""

user_text=input("Enter a text to analyze: ")

for character in (user_text):
    total_count= len(user_text)
    for user_text in (ascii_string):
        ascii_count=len(user_text)

print("Total number of characters: ", total_count)
print("Total number of ASCII characters: ", ascii_count)
print("Total number of non-ASCII characters: ", total_count-ascii_count)

Answer 1

是的，您确实使用了不合适的算法。对于输入字符串中的每个字符，您将保存整个输入字符串的长度，然后查看ASCII字符串中的每个字符并保存整个输入字符串的长度。试。

相反，将＆＃34;的所有布尔值加起来是在ASCII字符串＆＃34;通过将生成器传递给sum()，这将添加所有这些布尔值（True为1而False为0）：

ascii_string = set("""!"#$%&\'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\\]^_`abcdefghijklmnopqrstuvwxyz{|}~""")

user_text = input("Enter a text to analyze: ")

total_count = len(user_text)
ascii_count = sum(c in ascii_string for c in user_text)

print("Total number of characters:", total_count)
print("Total number of ASCII characters:", ascii_count)
print("Total number of non-ASCII characters:", total_count-ascii_count)

Answer 2

更好、更简单、更快捷的方法：


>>> s = "asdmlfjkéàç&-è'("
>>> ascii_count = len(s.encode("ascii", "ignore"))
>>> ascii_count
12

Python ASCII字符数

2 个答案: