Question

我正在努力应对这次更新...

我想更新表result中的列#b，其中columna_1列来自下面选择的最后一行。匹配字段为id_car。

因此，如果您运行下面的选择，则columna_1的最后一行为42229.56230859，#b的唯一记录为：

id_car = 1
result = 42229.56230859

任何人都可以帮忙吗？感谢!!!

CREATE TABLE #b(
      id_car int,
      result money
      )
INSERT INTO #b VALUES (1,0)



CREATE TABLE #f(
      id_car int,
      fecha  datetime,
      sales money
      )
INSERT INTO #f VALUES (1,'2010-10-31',1.10912)
INSERT INTO #f VALUES (1,'2010-11-30',1.77227)
INSERT INTO #f VALUES (1,'2010-12-31',0.66944)
INSERT INTO #f VALUES (1,'2011-01-31',0.34591)
INSERT INTO #f VALUES (1,'2011-02-28',1.73468)
INSERT INTO #f VALUES (1,'2011-03-31',1.50102)
INSERT INTO #f VALUES (1,'2011-04-30',0.87270)
INSERT INTO #f VALUES (1,'2011-05-31',1.51555)

;with ctesource as 
(
    select
        id_car, fecha, sales, 
        sum( log( 1e0 + sales ) ) over ( partition by id_car order by fecha rows unbounded preceding) as LogAssetValue
    from
        #f
        WHERE id_car= 1 and fecha > '2010-10-30'
)
select convert(varchar, fecha, 104) AS fecha1, fecha, 
 CAST(SUM(exp(LogAssetValue)-1)*100  AS numeric(20, 8)) as columna_1
from ctesource 
GROUP BY fecha
order by fecha;

Answer 1

的 SqlFiddleDemo

;with ctesource as ( SELECT id_car, fecha, sales, sum( log( 1e0 + sales ) ) over ( partition by id_car order by fecha rows unbounded preceding) as LogAssetValue, row_number() over (order by fecha) as rn FROM f WHERE id_car= 1 and fecha > '2010-10-30' ) SELECT convert(varchar, fecha, 104) AS fecha1, fecha, rn, CAST(SUM(exp(LogAssetValue)-1)*100 AS numeric(20, 8)) as columna_1 FROM ctesource GROUP BY fecha, rn HAVING rn = (SELECT max(rn) from ctesource)

SQl：更新表，其中包含select的最后一行

1 个答案: