Question

我在ruby中有一个multidimentional数组，如下所示：[[a, b, c], [d, e, f], [g, h, i]]我想用这个函数.gsub!(/\s+/, "")删除每个数组的每个第二个对象中的空格。所以它基本上就像在做：[[a, b.gsub!(/\s+/, ""), c], [d, e.gsub!(/\s+/, ""), f], [g, h.gsub!(/\s+/, ""), i]]

我有点困惑，我怎么能这样做？

Answer 1

arr = [[a, b, c], [d, e, f], [g, h, i]]

就地：

arr.each { |a| a[1].delete! ' ' }

不可变：

arr.dup.each { |a| a[1].delete! ' ' }

Answer 2

arr = [["Now is", "the time for", "all"],
       ["good", "people to come", "to", "the"],
       ["aid of", "their bowling", "team"]]

arr.map { |a,b,*c| [a, b.delete(' '), *c] }
  #=> [["Now is", "thetimefor", "all"],
  #    ["good", "peopletocome", "to", "the"],
  #    ["aid of", "theirbowling", "team"]]

改变arr：

arr.map! { |a,b,*c| [a, b.delete(' '), *c] }

Answer 3

arr = [[a, b, c], [d, e, f], [g, h, i]]

arr.map! do |el|
  el[1].gsub!(/\s+/, "")
  el
end

注意：这会改变您的原始数组，这可能是您不想要的。

在ruby中替换多维数组中的元素

3 个答案: