Question

我的尺寸为98 x 102的图像。光盘尺寸为11 270字节。我需要从这个图像中获取没有服务信息的字节数组。我试着做下一个：

MySystemInfo Msi;
puts(Msi.getOsInfo());

char* MySystemInfo::getOsInfo()
{
    OSVERSIONINFOEX osver;
    BOOL bOsVersionInfoEx;
    HKEY hKey;
    LONG lRet;
    char* RtTmpOsInfo= (char *) malloc(sizeof(char)*70);
    char* s1=(char *) malloc(sizeof(char)*20);
    char* s2=(char *) malloc(sizeof(char)*50);


    // Try calling GetVersionEx() using the OSVERSIONINFOEX structure.
    // If that fails, try using the OSVERSIONINFO structure.
    ZeroMemory(&osver, sizeof(OSVERSIONINFOEX));
    osver.dwOSVersionInfoSize = sizeof(OSVERSIONINFOEX);
    if(!(bOsVersionInfoEx = GetVersionEx((OSVERSIONINFO *) &osver)))
    {
        osver.dwOSVersionInfoSize = sizeof(OSVERSIONINFO);
        if(!GetVersionEx((OSVERSIONINFO *) &osver))
            return "";
    }


    switch (osver.dwPlatformId)
    {
        //Test for the Windows NT product family.
        case VER_PLATFORM_WIN32_NT:

            if(osver.dwMajorVersion <4> BUFSIZE) return "";
            sprintf( s1,"v%d.%d "+ osver.dwMajorVersion, osver.dwMinorVersion);
            // Test for the specific product family.
            if(osver.dwMinorVersion==0){
                if(osver.dwMajorVersion == 5) sprintf(s2,"Microsoft Windows 2000\n");
                else if(osver.dwMajorVersion == 6) sprintf(s2,"Microsoft Windows Vista\n");
            }

            else if(osver.dwMinorVersion==1){
                if(osver.dwMajorVersion == 5) sprintf(s2,"Microsoft Windows XP\n");
                else if(osver.dwMajorVersion == 6) sprintf(s2,"Microsoft Windows 7\n");
            }
            else if(osver.dwMinorVersion==2){
                if(osver.dwMajorVersion == 5) sprintf(s2,"Microsoft Windows Server 2003 family\n");
            }
            else sprintf(s2,"unknown OS\n");
        break;

    }
    strcat(RtTmpOsInfo,s1);     
    strcat(RtTmpOsInfo,s2);

    //lRet/* = RegOpenKeyEx(HKEY_LOCAL_MACHINE, L"SOFTWARE\\Microsoft\\WindowsNT\\CurrentVersion\\Hotfix\\Q246009", 0, KEY_QUERY_VALUE, &hKey);
    //  printf("Service Pack 1 (Build %d)\n", osver.dwBuildNumber & 0xFFFF);*/

    return RtTmpOsInfo;
}

通过这种方式我得到带有图像头的数组，因为get数组的长度是11 270。

标题大小是否正确= 11270 - （98 * 102）？因为这个结果是1274。

我正在尝试在控制台应用中执行此操作。

如果不正确，我该怎么做？

Answer 1

我假设您需要从此位图获取RGB数据。您可以通过锁定/解锁位图中的数据来获取对原始数据的访问权限。来自MSDN https://msdn.microsoft.com/en-us/library/5ey6h79d(v=vs.110).aspx的示例代码：

        // Create bitmap.
        Bitmap bmp = new Bitmap("c:\\photo.jpg");

        // Lock the bitmap's bits.  
        Rectangle rect = new Rectangle(0, 0, bmp.Width, bmp.Height);
        System.Drawing.Imaging.BitmapData bmpData =
            bmp.LockBits(rect, System.Drawing.Imaging.ImageLockMode.ReadWrite,
            bmp.PixelFormat);

        // Get the address of the first line.
        IntPtr ptr = bmpData.Scan0;

        // Declare an array to hold the bytes of the bitmap.
        int bytes  = Math.Abs(bmpData.Stride) * bmp.Height;
        byte[] rgbValues = new byte[bytes];

        // Copy the RGB values into the array.
        System.Runtime.InteropServices.Marshal.Copy(ptr, rgbValues, 0, bytes);

        // Set every third value to 255. A 24bpp bitmap will look red.  
        for (int counter = 2; counter < rgbValues.Length; counter += 3)
            rgbValues[counter] = 255;

        // Copy the RGB values back to the bitmap
        System.Runtime.InteropServices.Marshal.Copy(rgbValues, 0, ptr, bytes);

        // Unlock the bits.
        bmp.UnlockBits(bmpData);

获取没有头c＃的位图字节数组

1 个答案: