Question

假设我有这种数据格式

thingy=[[[(1,2),(3,4)],[(5,6),(7,8)]],[[(-1,-2),(-3,-4)],[(-5,-6),(-7,-8)]]]

我希望将（9,9）追加到每个子子列表中，以便：

thingy_2=[[[(1,2),(3,4),(9,9)],[(5,6),(7,8),(9,9)]],[[(-1,-2),(-3,-4),(9,9)],[(-5,-6),(-7,-8),(9,9)]]]

有没有办法做以下事情：

thingy_2=[[i for i in j].append((9,9)) for j in thingy] #this doesn't work though

我知道如果我这样做：

[[i.append((9,9)) for i in j] for j in thingy]

这会将（9,9）附加到thingy列表中，但不会帮助我创建新列表。

thingy_2=[[i.append((9,9)) for i in j] for j in thingy]
"""
In [302]: thingy_2
Out[301]: [[None, None], [None, None]]
""""

Answer 1

append()对原始list执行操作，然后return执行值None。您需要添加extend list。例如，[1,2] + [3,4]为[1,2,3,4]。

>>> thingy=[[[(1,2),(3,4)],[(5,6),(7,8)]],[[(-1,-2),(-3,-4)],[(-5,-6),(-7,-8)]]]
>>> thingy_2 = [[l + [(9,9)] for l in s] for s in thingy]
>>> thingy_2
[[[(1, 2), (3, 4), (9, 9)], [(5, 6), (7, 8), (9, 9)]], [[(-1, -2), (-3, -4), (9, 9)], [(-5, -6), (-7, -8), (9, 9)]]]

Answer 2

代码就像嵌套的for循环一样简单

thingy=[[[(1,2),(3,4)],[(5,6),(7,8)]],[[(-1,-2),(-3,-4)],[(-5,-6),(-7,-8)]]]
for i in thingy:
    for e in i:
       e.append((9,9))

如果您需要保留旧列表，只需弄乱这样的副本：

thingy_copy = thingy[:]
for i in thingy:
    for e in i:
       e.append((9,9))

如何将元组附加到子子列表？

2 个答案: