Question

我想在CMD中实现以下目标：

将使用dir /s filename
一旦发现，它将带我走上那条道路。示例：我现在在C:\，如果在C:\test中找到该文件，则会在命令提示符下打开C:\test。

或者，我想将找到的文件复制到我将指定的路径。我只是不知道该怎么做，因为我不知道文件存储的路径（每次都不同）。

提前致谢！

Answer 1

我的问题与您的问题相混淆，但我会尝试引导您完成我编写的批处理代码，以帮助您解决此问题。

dir /b /s "test.txt" > "%userprofile%/Desktop/result.txt"

::find the file path to the file you want to find and insert it in a .txt file
::you made called result.txt (also %userprofile% is a variable that brings you to
::your user directory ex C:/users/admin)

for /F "tokens=*" %%A in (%userprofile%/desktop/result.txt) do (
    set var1=%%A
)  

::set the variable var1 equal to the first (well... only) line in the file.
::I could explain what that for loop means in detail but just remember that %%A
::is a variable set from what was found when looping through the result.txt.
xcopy /s "%var1%" "C:/wherever/you/want/it/to/go"

这有帮助??

搜索文件并在CMD中打开路径

1 个答案: