Question

我有以下格式的示例xml文件。如何使用Powershell直接访问键的值？

例如：$ xml.array.dict.key.name - ＆gt;鲍勃，凯特，约翰

$xml = @'
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<array>
    <dict>
        <key>name</key>
        <string>bob</string>
        <key>age</key>
        <string>35</string>
        <key>gender</key>
        <string>male</string>
    </dict>
    <dict>
        <key>name</key>
        <string>kate</string>
        <key>age</key>
        <string>12</string>
        <key>gender</key>
        <string>female</string>
    </dict>
    <dict>
        <key>name</key>
        <string>john</string>
        <key>age</key>
        <string>57</string>
        <key>gender</key>
        <string>male</string>
    </dict>
</array>
</plist>
'@

如何将xml转换为Powershell对象，如下所示？

输出

name   age   gender
---    --    -----
bob    35    male
kate   12    female
john   57    male

这就是我的尝试。

$xmldata = [xml]$xml
$xmldict = $xmldata.plist.array.dict
$xmldict

这给出了输出

key                                    string
---                                    ------
{name, age, gender}                    {bob, 35, male}
{name, age, gender}                    {kate, 12, female}
{name, age, gender}                    {john, 57, male}

$ xmldict.key

name
age
gender
name
age
gender
name
age
gender

Answer 1

这是一种奇怪的格式，你依赖于键/字符串元素对的顺序。但是，这对您的XML进行了测试：

$xml.plist.array.dict | 
    Foreach {
        $vals = $_.SelectNodes('string'); $_.SelectNodes('key') | 
        Foreach {$ht=@{};$i=0} {$ht[$_.'#text'] = $vals[$i++].'#text'} `
                {new-object psobject -property $ht}
    }

这个版本本质上更通用 - 不依赖于string元素名称：

$xml.plist.array.dict | 
    Foreach {
        $_.SelectNodes('key') | 
        Foreach {$ht=@{}} {$ht[$_.'#text'] = $_.NextSibling.'#text'} `
                {new-object psobject -property $ht}
    }

Powershell xml访问密钥对值

1 个答案: