需要帮助创建一个数组并在另一个函数中编辑它并将其发送回初始函数

Question

我在int main中创建了一个传递给GenerateMap的数组，然后GenerateMap函数遍历数组并分配每个项目。在分配了每个项目之后，我希望它返回到int main，以便我可以在以后使用它，但我一直在收到错误。经过几次尝试后，我通过参考传递阵列来跟随Thenewboston的指示。但我仍然在代码中遇到错误。有人可以向我解释我应该做什么在另一个函数中创建地图吗？

错误

  

prog.cpp: In function 'int main()': prog.cpp:22:17: error: cannot convert 'std::string (*)[MapDimension][MapDimension] {aka std::basic_string<char> (*)[MapDimension][MapDimension]}' to 'std::string** {aka std::basic_string<char>**}' for argument '1' to 'void GenerateMap(std::string**)' GenerateMap(&Map); ^ prog.cpp: In function 'void GenerateMap(std::string**)': [NEW ERROR] prog.cpp:70:31: error: no match for 'operator*' (operand type is 'std::string {aka std::basic_string<char>}') cout <<"[" << *Map[i][j] << "]" << " ";

CODE

int main() {
string Map[MapDimension][MapDimension];
GenerateMap(&Map);

}





void GenerateMap(string *Map[]) {
  srand(time(NULL));
  string x;

for (int i = 0; i <= MapDimension-1; ++i) {

    for (int j = 0; j <= MapDimension-1; ++j) 

            {

            int random = rand() % 6;
                switch  (random) 
                {
                     case 0:
                      x = " D ";
                      break;

                      case 1:
                      x = " F ";
                      break;

                      case 2:
                      x = " P ";
                      break;

                      case 3:
                      x = " M ";
                      break;

                      case 4:
                      x = " L ";
                      break;

                      case 5:
                      x = " S ";
                      break;
                }

            Map[i][j] = x;

            cout <<"[" << *Map[i][j] << "]" << "  ";
            }
    cout << endl;

}




}

Answer 1

你需要一个分号：

string Map[MapDimension][MapDimension] 

应该是

string Map[MapDimension][MapDimension];