我有一个带有Fragment的Activity和IntentService。当我单击按钮对话框片段打开并输入我的数据。之后我单击Ok并调用getActivity()。startService(intent)。服务通过LocalBroadcastManager调用sendBroadcast(intent),但是没有调用onReceive()方法。怎么了?有我的BroadcastReceiver
private BroadcastReceiver mApiBroadcastReceiver = new BroadcastReceiver() {
@Override
public void onReceive(Context context, Intent intent) {
Log.d("tag", intent.getAction());
switch (intent.getAction()) {
case "register":
showMessage(intent.getStringExtra(ApiService.EXTRA_ANSWER));
break;
case "authorize":
showProfile((User) intent.getParcelableExtra(ApiService.EXTRA_USER));
break;
default:
break;
}
}
};
我在这里注册接收器
@Override
protected void onResume() {
super.onResume();
LocalBroadcastManager.
getInstance(this).
registerReceiver(mApiBroadcastReceiver, new IntentFilter(ApiService.API_BROADCAST));
}
我的onDestroy方法
@Override
protected void onPause() {
super.onPause();
LocalBroadcastManager.getInstance(this).unregisterReceiver(mApiBroadcastReceiver);
}
和我发送广播的服务方法
private void sendMessage(Object answer) {
Intent intent = new Intent(API_BROADCAST);
if (answer instanceof String) {
intent.setAction("register");
Log.d("tag", answer.toString());
intent.putExtra(EXTRA_ANSWER, answer.toString());
} else if (answer instanceof User) {
intent.setAction("authorize");
intent.putExtra(EXTRA_USER, (User) answer);
}
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}
答案 0 :(得分:2)
你不应该致电intent.setAction()
。
您正在倾听行动ApiService.API_BROADCAST
的意图:
new IntentFilter(ApiService.API_BROADCAST)
; new Intent(ApiService.API_BROADCAST)
; 没关系,但是如果你以后拨打intent.setAction("register")
,你就会覆盖你设置的第一个动作。
相反,请尝试将子操作字符串作为Extra
传递:
private void sendMessage(Object answer) {
Intent intent = new Intent(API_BROADCAST);
if (answer instanceof String) {
intent.putExtra(EXTRA_WHAT, "register");
intent.putExtra(EXTRA_ANSWER, answer.toString());
} else if (answer instanceof User) {
intent.putExtra(EXTRA_WHAT, "authorize");
intent.putExtra(EXTRA_USER, (User) answer);
}
LocalBroadcastManager.getInstance(this).sendBroadcast(intent);
}