Question

我有这段代码

try:
    response = requests.post(url, data=json.dumps(payload))
except (ConnectionError, HTTPError):
    msg = "Connection problem"
    raise Exception(msg)

现在我想要以下

if status_code == 401
   login() and then try request again
if status_code == 400
   then send respose as normal
if status_code == 500
   Then server problem , try the request again and if not successful raise   EXception

现在这些是状态代码，我不知道如何将状态代码与异常混合。我也不知道HttpError会涵盖哪些代码

Answer 1

请求在您的请求对象中有一个名为raise_for_status的调用，如果在400到500范围内返回任何代码，则会引发HTTPError异常。

raise_for_status的文档是here

所以，你可以做的，就是在你打电话之后：

response = requests.post(url, data=json.dumps(payload))

您拨打raise_for_status作为

response.raise_for_status()

现在，您已经捕获了这个异常，这很好，所以您只需检查错误中的状态代码。您可以通过两种方式使用它。您可以从异常对象或请求对象中获取它。以下是此示例：

from requests import get
from requests.exceptions import HTTPError

try:
    r = get('http://google.com/asdf')
    r.raise_for_status()
except HTTPError as e:
    # Get your code from the exception object like this
    print(e.response.status_code)
    # Or you can get the code which will be available from r.status_code
    print(r.status_code)

因此，考虑到上述情况，您现在可以在条件语句中使用状态代码

Answer 2

https://docs.python.org/2/library/urllib2.html#urllib2.URLError

code
An HTTP status code as defined in RFC 2616. This numeric value 
corresponds to a value found in the dictionary of codes as found in 
BaseHTTPServer.BaseHTTPRequestHandler.responses.

您可以从HTTPError成员的code获取错误代码，如此

try:
    # ...
except HTTPError as ex:
    status_code = ex.code

如何使用python请求对不同情况使用异常

2 个答案: