三元运算符Ruby put

Question

我不明白为什么以下声明提出：     “一个不到两个！”到了屏幕而不是直接放在puts之前的代码？

以下是声明：

X = 1 < 2 
puts X == true ? "One is less than two!" : "One is not less than two."

有人可以解释原因吗？

Answer 1

您的问题的答案是the ternary operator has higher precedence than the method call，*的优先级高于+，因此在将结果传递给方法之前评估三元表达式。

换句话说，这个：

puts X == true ? "One is less than two!" : "One is not less than two."

..相当于：

puts(X == true ? "One is less than two!" : "One is not less than two.")

..和不这个：

puts(X == true) ? "One is less than two!" : "One is not less than two."

Answer 2

问号的左侧需要是真还是假。如果它是真的，它将执行结肠的左侧。如果为false，则执行右侧。所以它应该是：

1 < 2 ? puts "One is less than two!" : puts "One is not less than two"