Question

我试图打开联系意图并让用户选择多重联系人
意图呼叫：

Intent pickContactIntent = new Intent(Intent.ACTION_PICK, Uri.parse("content://contacts"));
pickContactIntent.setType(ContactsContract.CommonDataKinds.Phone.CONTENT_TYPE); // Show user only contacts / phone numbers
startActivityForResult(pickContactIntent, PICK_CONTACT_REQUEST);

使用这种方法，用户只能选择一个联系人..我怎样才能让他选择很多联系人然后获得他选择的所有号码？

Answer 1

有两个人要这样做！

1.在意图中设置MAX挑选限制：

public static final int REQUEST_CODE_PICK_CONTACT = 1;
public static final int  MAX_PICK_CONTACT= 10;

private void launchMultiplePhonePicker() { 

    Intent phonebookIntent = new Intent("intent.action.INTERACTION_TOPMENU");
    phonebookIntent.putExtra("additional", "phone-multi");
    phonebookIntent.putExtra("maxRecipientCount", MAX_PICK_CONTACT);
    phonebookIntent.putExtra("FromMMS", true);
    startActivityForResult(phonebookIntent, REQUEST_CODE_PICK_CONTACT);

 }

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {

    if(resultCode==RESULT_OK) {
        if(requestCode == REQUEST_CODE_PICK_CONTACT) {

            Bundle bundle =  data.getExtras();

            String result= bundle.getString("result");
            ArrayList<String> contacts = bundle.getStringArrayList("result");

            Log.i(TAG, "launchMultiplePhonePicker bundle.toString()= " + contactsPick.toString() );
        }
    }

    super.onActivityResult(requestCode, resultCode, data);
}

注意：每个操作系统版本和设备可能有所不同，并且可能不适用于所有操作系统版本和设备。

OR

这样做：

以编程方式阅读联系人并在活动中的ListView中显示它们，然后使用ListView项目中的复选框并允许选择多个项目。

e.g。如何读取系统联系人：

Cursor cursor = getContentResolver().query(ContactsContract.Contacts.CONTENT_URI,null, null, null, null); 
while (cursor.moveToNext()) {
    String contactId = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts._ID));
    String hasPhone = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER)); 
    String name = cursor.getString(cursor.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
    if("1".equals(hasPhone) || Boolean.parseBoolean(hasPhone)) { 
        // You know it has a number so now query it like this
        Cursor phones = myActivity.getContentResolver().query( ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, ContactsContract.CommonDataKinds.Phone.CONTACT_ID +" = "+ contactId, null, null); 
        while (phones.moveToNext()) { 
            String phoneNumber = phones.getString(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
            int itype = phones.getInt(phones.getColumnIndex(ContactsContract.CommonDataKinds.Phone.TYPE));

            final boolean isMobile =
                itype == ContactsContract.CommonDataKinds.Phone.TYPE_MOBILE ||
                itype == ContactsContract.CommonDataKinds.Phone.TYPE_WORK_MOBILE;

            // Do something here with 'phoneNumber' such as saving into 
            // the List or Array that will be used in your 'ListView'.

        } 
        phones.close();
    }
}

多个选择的联系意图

1 个答案: