时间:2010-07-25 10:27:20

标签: java ant xsd jaxb schemagen

1 个答案:

答案 0 :(得分:2)

你可能很容易写一些东西,然后从Ant调用它:

import java.io.File;
import java.io.IOException;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.SchemaOutputResolver;
import javax.xml.transform.Result;
import javax.xml.transform.stream.StreamResult;

public class SchemaGenerator {

    public static void main(String[] args) throws Exception {
        String contextPath = args[0];
        String outputDir = args[1];
        JAXBContext jc = JAXBContext.newInstance(contextPath);
        jc.generateSchema(new MySchemaOutputResolver(schemaFileName));
    }

    private static class MySchemaOutputResolver extends SchemaOutputResolver {

        private String outputDir;

        public MySchemaOutputResolver(String outputDir) {
            this.outputDir = outputDir;
        }

        public Result createOutput(String namespaceURI, String suggestedFileName) throws IOException {
            File file = new File(outputDir + "/" + suggestedFileName);
            StreamResult result = new StreamResult(file);
            result.setSystemId(file.toURI().toURL().toString());
            return result;
        }

    }   

}

在您的上下文路径中,您需要一个jaxb.in​​dex文件,其中包含要包含在JAXBContext中的类列表。或者您可以将类名传递给SchemaGenerator类并通过ClassLoader加载它们。