Question

我试图通过汇总oracle函数使用一个组，但没有正确使用它。

这是我的数据格式（L1_Proj_ID是1级项目ID等.....）

Proj_ID  Hours_Charged L1_Proj_ID  L2_Proj_ID L3_Proj_ID     L4_Proj_ID  
-------------------------------------------------------------------------  
1100.10         20       1100        1100.10    Null           Null  
1100.11.01      30       1100        1100.11    1100.11.01     Null  
1100.11.02      40       1100        1100.11    1100.11.02     Null  
1100.12.01.01   50       1100        1100.12    1100.12.01     1100.12.01.01

我需要得到累计总数，我的输出应该是

Proj_Level  Hours_Charged  
--------------------------  
1100            140  
1100.10          20  
1100.11          70  
1100.11.01       30  
1100.11.02       40   
1100.12          50   
1100.12.01       50  
1100.12.01.01    50

请告诉我是否还有其他简单方法。

截至目前，我可以获得这样的数据......

select 
  L1_proj_id, 
  sum(hours_charged) as hours_charged 
from table  
group by 
  l1_proj_id 
union all   
select 
  L2_proj_id, 
  sum(hours_charged) as hours_charged 
from table 
group by 
  21_proj_id  
union all  
select 
  L3_proj_id, 
  sum(hours_charged) as hours_charged 
from table 
group by 
  l3_proj_id  
union all  
select 
  L4_proj_id, 
  sum(hours_charged) as hours_charged 
from table 
group by 
  l4_proj_id

Answer 1

这不使用rollup，但我认为它可能会带来您的结果。从本质上讲，我将您的列排除在行之外。如果您的内容发生变化，它也应该相对易于扩展。

with levels as (
  select level id
  from dual
  connect by level <= 4
),
all_data as (
  select
    case l.id
      when 1 then l1_proj_id
      when 2 then l2_proj_id
      when 3 then l3_proj_id
      when 4 then l4_proj_id
    end as project_id,
    t.hours_charged
  from
    table t,
    levels l
)
select
  project_id, sum (hours_charged) as hours_charged
from all_data
where project_id is not null
group by project_id

如何在oracle中使用汇总功能

1 个答案: