我试图了解vfio如何在pci上运行。 我已阅读https://www.kernel.org/doc/Documentation/vfio.txt,我正在根据它进行测试。 在某些时候,我的代码看起来像这样:
/* Get pci device information (number of regions and interrupts...) */
ret = ioctl(vfio_dev_fd, VFIO_DEVICE_GET_INFO, &device_info);
if (ret) {
printf(" %s cannot get device info, "
"error %i (%s)\n", pci_addr, errno, strerror(errno));
close(vfio_dev_fd);
return -1;
}
printf ("found %d regions in the device\n", device_info.num_regions);
我不明白的是,最后一个printf显示了9个(9个)区域! 查看我的PCI设备的配置空间,我可以看到:
cat /sys/bus/pci/devices/0000\:06\:00.0/config | hd
00000000 e4 14 81 16 00 04 10 00 10 00 00 02 10 00 00 00 |................|
00000010 04 00 de f3 00 00 00 00 04 00 df f3 00 00 00 00 |................|
00000020 00 00 00 00 00 00 00 00 00 00 00 00 28 10 6e 02 |............(.n.|
00000030 00 00 00 00 48 00 00 00 00 00 00 00 0a 01 00 00 |....H...........|
00000040
我是PCI的新手,但我对此的解释是这个板上只有两个BARS(0和2)。而我虽然PCI的最大区域数(BAR?)是6。
但是有一点迹象表明我误解了一些东西:上面提到的内核文档说明:
对于PCI设备,配置空间是一个区域
所以这可能导致我正在寻找的3个区域...仍然它说9 ... 什么是pci_vfio的PCI区域?它们如何编号和访问?...
感谢。
答案 0 :(得分:0)
来自vfio.h:
/*
* The VFIO-PCI bus driver makes use of the following fixed region and
* IRQ index mapping. Unimplemented regions return a size of zero.
* Unimplemented IRQ types return a count of zero.
*/
enum {
VFIO_PCI_BAR0_REGION_INDEX,
VFIO_PCI_BAR1_REGION_INDEX,
VFIO_PCI_BAR2_REGION_INDEX,
VFIO_PCI_BAR3_REGION_INDEX,
VFIO_PCI_BAR4_REGION_INDEX,
VFIO_PCI_BAR5_REGION_INDEX,
VFIO_PCI_ROM_REGION_INDEX,
VFIO_PCI_CONFIG_REGION_INDEX,
/*
* Expose VGA regions defined for PCI base class 03, subclass 00.
* This includes I/O port ranges 0x3b0 to 0x3bb and 0x3c0 to 0x3df
* as well as the MMIO range 0xa0000 to 0xbffff. Each implemented
* range is found at it's identity mapped offset from the region
* offset, for example 0x3b0 is region_info.offset + 0x3b0. Areas
* between described ranges are unimplemented.
*/
VFIO_PCI_VGA_REGION_INDEX,
VFIO_PCI_NUM_REGIONS
};
因此,这些附加区域是一种提供对配置空间,选项ROM和VGA特定I / O(端口和传统帧缓冲区0xa0000 ... 0xbffff窗口)的访问的方法。