Question

我将此错误显示为标题。根据文件，我添加了＆＃34; slug_url_kwarg =＆＃39;结果＆＃39;＆＃34;，（结果是应用名称）。它不起作用，然后我添加＆＃34; def get_object（self）：＆＃34;，它返回错误为＆＃34; id是一个KeyError＆＃34;

它自己创建的数据库是主要的：＆＃34; id＆＃34;，所以我使用了这个＆＃34; id＆＃34;作为slug_field。这是对的吗？
您认为我是否有必要使用UpdateView？我希望html在提交表单后显示结果（使用ajax）？

事先准备好你的回复。

网址

url(r'^result_list/$',ResultView.as_view(),name='result'),

views.py

class ResultView(UpdateView):
    context_object_name = 'result_list'
    template_name = 'result_list.html'
    form_class = InputForm
    slug_field = 'result.id' ---here means the pk,right?
    slug_url_kwarg = 'result'



    def get_queryset(self):
        return Result.objects.all()

    def post(self, request, *args, **kwargs):
        form = InputForm(request.POST)
        if form.is_valid():
            if self.request.is_ajax():
                company = form.cleaned_data['company']
                region = form.cleaned_data['region']

                queryset=Result.objects.filter(region=region)
                return HttpResponse(simplejson.dumps(to_json),mimetype='application/json')
        else:
             return HttpResponse(form.errors)

    def get_context_data(self, **kwargs):
        context = super(ResultView, self).get_context_data(**kwargs)
        context["sales"] = self.get_queryset().aggregate(Sum('sales'))

    def get_object(self):
        object = get_object_or_404(Result,id=self.kwargs['id'])  <!here is not correct--->
        return object

回溯

File "C:\Python27\lib\site-packages\django-1.8.3-py2.7.egg\django\core\handlers\base.py" in get_response
  132.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\Python27\lib\site-packages\django-1.8.3-py2.7.egg\django\views\generic\base.py" in view
  71.             return self.dispatch(request, *args, **kwargs)
File "C:\Python27\lib\site-packages\django-1.8.3-py2.7.egg\django\views\generic\base.py" in dispatch
  89.         return handler(request, *args, **kwargs)
File "C:\Python27\lib\site-packages\django-1.8.3-py2.7.egg\django\views\generic\edit.py" in get
  267.         self.object = self.get_object()
File "C:\Users\user\Desktop\project\result\views.py" in get_object
  54.         object = get_object_or_404(Result,id=self.kwargs['id'])

Exception Type: KeyError at /result_list/
Exception Value: 'id'

Answer 1

你忘了映射网址格式，你不需要在你的情况下指定slug_field和slug_url_kwarg：

url(r'^dupont_list/(?P<pk>[0-9]+)/$', DupontView.as_view(), name='dupont'),

必须使用对象pk或slug调用通用详细信息viewResult

1 个答案: