最终编辑: 谢谢大家的帮助。我一直在尝试在index.php而不是submit.php中编写与连接相关的所有代码。它现在已经解决了。
编辑:
我已根据您的反馈更新了代码。 我现在能够将值传递给数据库,但问题是它只显示空结果。这是更新的代码。
<form action="submit.php" method="post" class="form-horizontal">
<div class="form-group">
<label for="name" class ="col-lg-2 control-label" > Name</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="name" name="name" placeholder="Enter your Name" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="email" class ="col-lg-2 control-label" > Email</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="email" name="email" placeholder="Enter your email address" required>
</div>
</div>
</div> <div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="subject" class ="col-lg-2 control-label" > Subject</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="subject" name="subject" placeholder="Your Subject" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal">
<div class="form-group">
<label for="message" class ="col-lg-2 control-label" > Message</label>
<div class="col-lg-7">
<textarea name="message" class="form-control" id ="message" cols="20" rows="3" placeholder="Your Message"></textarea>
</div>
</div> <!-- end form -->
<div class="col-lg-1">
</div>
<div class="form-group">
<div class="col-lg-7 col-lg-offset-2">
<button type="submit" name="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</form>
PHP代码:
<?php
if (isset($_POST)) {
$conn = mysqli_connect($servername, $username, $password, $db_name);// Establishing Connection with Server
mysqli_set_charset($conn, 'utf8');
if (!$conn) {
die("Database connection failed: " . mysqli_error($conn));
}
else
echo "connected successfully";
//Escaping string, not 100% safe, also consider validating rules and sanitization
$name = mysqli_real_escape_string($conn, $_POST['name']);
$email = mysqli_real_escape_string($conn, $_POST['email']);
$subject = mysqli_real_escape_string($conn, $_POST['subject']);
$message = mysqli_real_escape_string($conn, $_POST['message']);
$result = mysqli_query($conn, "INSERT INTO contact (user, email, subject, message) VALUES ('$name', '$email', '$subject', '$message')");
}
?>
Here is the snapshot of the database
我有一个使用HTML制作的表单。我想在数据库中提交表单时存储结果。连接成功但数据未存储在数据库中。
基本上,submit.php所做的只是发送文本“Successfully submited the form”。
这是我的代码:
<form action="submit.php" method="post" class="form-horizontal">
<div class="form-group">
<label for="name" class ="col-lg-2 control-label" > Name</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="name" placeholder="Enter your Name" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="email" class ="col-lg-2 control-label" > Email</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="email" placeholder="Enter your email address" required>
</div>
</div>
</div> <div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="subject" class ="col-lg-2 control-label" > Subject</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="subject" placeholder="Your Subject" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal">
<div class="form-group">
<label for="message" class ="col-lg-2 control-label" > Message</label>
<div class="col-lg-7">
<textarea name="message" class="form-control" id ="message" cols="20" rows="3" placeholder="Your Message"></textarea>
</div>
</div> <!-- end form -->
<div class="col-lg-1">
</div>
<div class="form-group">
<div class="col-lg-7 col-lg-offset-2">
<button type="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</form>
PHP代码:
$conn = mysqli_connect($servername, $username, $password, $db_name);// Establishing Connection with Server
mysqli_set_charset($conn, 'utf8');
if (!$conn) {
die("Database connection failed: " . mysqli_error($conn));
}
else
echo "connected successfully";
if (isset($_POST['submit'])) {
//Escaping string, not 100% safe, also consider validating rules and sanitization
$name = mysqli_real_escape_string($conn, $_POST['name']);
$email = mysqli_real_escape_string($conn, $_POST['email']);
$subject = mysqli_real_escape_string($conn, $_POST['subject']);
$message = mysqli_real_escape_string($conn, $_POST['message']);
$result = mysqli_query($conn, "INSERT INTO contact (user, email, subject, message) VALUES ('$name', '$email', '$subject', '$message');");
if ($result) {
$message="successfully sent the query!!";
}
else
{$message="try again!!";}
}
?>
答案 0 :(得分:1)
您的所有输入字段都没有name=""
属性,包括按钮。因此,这些字段都不会在$ _POST数组中发送。
将这样的name=""
属性添加到要发送给PHP的所有字段
<form action="submit.php" method="post" class="form-horizontal">
<div class="form-group">
<label for="name" class ="col-lg-2 control-label" > Name</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="name" name="name" placeholder="Enter your Name" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="email" class ="col-lg-2 control-label" > Email</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="email" name="email" placeholder="Enter your email address" required>
</div>
</div>
</div>
<div class="col-lg-1"></div>
<div class="form-horizontal" >
<div class="form-group">
<label for="subject" class ="col-lg-2 control-label" > Subject</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="subject" name="subject" placeholder="Your Subject" required>
</div>
</div>
</div>
<div class="col-lg-1"></div>
<div class="form-horizontal">
<div class="form-group">
<label for="message" class ="col-lg-2 control-label" > Message</label>
<div class="col-lg-7">
<textarea name="message" class="form-control" id ="message" name="message" cols="20" rows="3" placeholder="Your Message"></textarea>
</div>
</div> <!-- end form -->
<div class="col-lg-1"></div>
<div class="form-group">
<div class="col-lg-7 col-lg-offset-2">
<button type="submit" class="btn name="submit" btn-primary">Submit</button>
</div>
</div>
</form>
同样在submit.php
的代码中更改此内容,以便您看到实际的错误消息。
if ($result) {
$message="successfully sent the query!!";
} else {
$message="Insert failed : " . mysqli_error($conn);
}
echo $message;
虽然这确实假设您实际上在代码中的某处显示了$message
值,但您尚未向我们展示。
答案 1 :(得分:0)
试试这段代码: -
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
$conn = mysqli_connect($servername, $username, $password, $db_name);// Establishing Connection with Server
mysqli_set_charset($conn, 'utf8');
if (!$conn) {
die("Database connection failed: " . mysqli_error($conn));
}
else
echo "connected successfully";
//Escaping string, not 100% safe, also consider validating rules and sanitization
$name = mysqli_real_escape_string($conn, $_POST['name']);
$email = mysqli_real_escape_string($conn, $_POST['email']);
$subject = mysqli_real_escape_string($conn, $_POST['subject']);
$message = mysqli_real_escape_string($conn, $_POST['message']);
$result = mysqli_query($conn, "INSERT INTO contact (user, email, subject, message) VALUES ('$name', '$email', '$subject', '$message')");
echo "INSERT INTO contact (user, email, subject, message) VALUES ('$name', '$email', '$subject', '$message')";//die;
if ($result) {
$message="successfully sent the query!!";
}
else
{$message="try again!!";}
}
?>
<form action="index.php" method="post" class="form-horizontal">
<div class="form-group">
<label for="name" class ="col-lg-2 control-label" > Name</label>
<div class="col-lg-7">
<input type="text" class="form-control" name ="name" id ="name" placeholder="Enter your Name" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="email" class ="col-lg-2 control-label" > Email</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="email" name="email" placeholder="Enter your email address" required>
</div>
</div>
</div> <div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="subject" class ="col-lg-2 control-label" > Subject</label>
<div class="col-lg-7">
<input type="text" name="subject" class="form-control" id ="subject" placeholder="Your Subject" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal">
<div class="form-group">
<label for="message" class ="col-lg-2 control-label" > Message</label>
<div class="col-lg-7">
<textarea name="message" class="form-control" id ="message" cols="20" rows="3" placeholder="Your Message"></textarea>
</div>
</div> <!-- end form -->
<div class="col-lg-1">
</div>
<div class="form-group">
<div class="col-lg-7 col-lg-offset-2">
<button type="submit" class="btn btn-primary" name="submit">Submit</button>
</div>
</div>
</form>
答案 2 :(得分:0)
您必须在name
元素中添加button
属性,以便if (isset($_POST['submit']))
为true
。
请更改
<button type="submit" class="btn btn-primary">Submit</button>
到
<button type="submit" name="submit" class="btn btn-primary">Submit</button>
或
<input type="submit" name="submit" value="Submit" class="btn btn-primary" />
答案 3 :(得分:0)
首先,您必须为每个输入标记和按钮标记提供名称属性,以获得更好的方法:
<form action="submit.php" method="post" class="form-horizontal">
<div class="form-group">
<label for="name" class ="col-lg-2 control-label" > Name</label>
<div class="col-lg-7">
<input type="text" class="form-control" id ="name" name ="name" placeholder="Enter your Name" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="email" class ="col-lg-2 control-label" > Email</label>
<div class="col-lg-7">
<input type="text" class="form-control" name ="email" id ="email" placeholder="Enter your email address" required>
</div>
</div>
</div> <div class="col-lg-1">
</div>
<div class="form-horizontal" >
<div class="form-group">
<label for="subject" class ="col-lg-2 control-label" > Subject</label>
<div class="col-lg-7">
<input type="text" class="form-control" name ="subject" id ="subject" placeholder="Your Subject" required>
</div>
</div>
</div>
<div class="col-lg-1">
</div>
<div class="form-horizontal">
<div class="form-group">
<label for="message" class ="col-lg-2 control-label" > Message</label>
<div class="col-lg-7">
<textarea name="message" class="form-control" name ="message" id ="message" cols="20" rows="3" placeholder="Your Message"></textarea>
</div>
</div> <!-- end form -->
<div class="col-lg-1">
</div>
<div class="form-group">
<div class="col-lg-7 col-lg-offset-2">
<button type="submit" name ="submit" class="btn btn-primary">Submit</button>
</div>
</div>
</form>
在数据库中插入数据的Php代码:
<强> $result = mysqli_query($conn, "INSERT INTO contact (user, email, subject, message) VALUES ('".$name."', '".$email."', '".$subject."', '".$message."')");
强>