Question

这是我的地图条目的日志。这有两个相同的密钥存在。这怎么可能？

 Map<String, Objects> map = new HashMap<String, Objects>();

 addContact("+917111111111");
 addContact("+919222222222");
 addContact("+919222222222");

 private void addContact(String number){
        if(TextUtils.isEmpty(number))return;

        number = number.trim();
        number = number.replaceAll("-", "");
        number = number.replaceAll(" ", "");

        if(!map.containsKey(number)) {
            map.put(number, null);
        }
    }
    /* While debugging in android studio. I have found the map have below entry.
        0 = {HashMap$HashMapEntry@3798} "+919222222222" -> "null"
        1 = {HashMap$HashMapEntry@3832} "‪+919222222222" -> "null"
        2 = {HashMap$HashMapEntry@3694} "+917111111111" -> "null"
    */
    map.containsKey("+919222222222");// ==> return false

为什么会这样？

实际任务：

private void getContacts(){
    try {
        Cursor cursor = null;
        StringBuffer sb = new StringBuffer();

        Map<String, Object> map = new HashMap<String, Object>();
        try {
            String strOrder = ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME + " ASC";
            cursor = getContentResolver().query(ContactsContract.CommonDataKinds.Phone.CONTENT_URI, null, null, null, strOrder);
            int contactIdIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone._ID);
            int nameIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.DISPLAY_NAME);
            int phoneNumberIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER);
            int photoIdIdx = cursor.getColumnIndex(ContactsContract.CommonDataKinds.Phone.PHOTO_ID);
            cursor.moveToFirst();
            do {
                String idContact = cursor.getString(contactIdIdx);
                String name = cursor.getString(nameIdx);
                String phoneNumber = cursor.getString(phoneNumberIdx);
                //...
                phoneNumber = getFormatedNumber(phoneNumber);

                //as map key same phone number can not be two times
                if(!map.containsKey(phoneNumber)) {
                    map.put(phoneNumber, null);
                    sb.append("\nPhone Number:--- " + phoneNumber + "\nUser Name:--- "
                            + name);
                    sb.append("\n----------------------------------");
                }
            } while (cursor.moveToNext());
        } catch (Exception e) {
            e.printStackTrace();
        } finally {
            if (cursor != null) {
                cursor.close();
            }
        }
        textView.setText(sb); //As in output it shows one number showing two times
    } catch (Exception e) {
        e.printStackTrace();
    }
}

 private String getFormatedNumber(String number){
        if(TextUtils.isEmpty(number))return null;

        number = number.trim();
        number = number.replaceAll("-", "");
        number = number.replaceAll(" ", "");

        return number;
    }

Answer 1

在所有讨论之后，我发现问题就像问题一样，因为我的字符串中的unicode字符附加在调试时是不可见的，但是如果我们复制到记事本中则清楚可见。如：＆＃39; \ u202A \ u202A + 91922222222 \ u202A \ u202C＆＃39;

虽然它的containsKey方法返回false，HashMap有关键吗？

1 个答案: