让我从这开始说,我知道我不应该粗暴强迫程序,但我有点陷入僵局,目的是使用一个数组的元素基本上“排序”另一个数组的元素。
假设:
start = 1
字符:H,A,C,E,B,D,F,G 链接:0,4,5,6,2,3,7,0
所以你从第一个元素A开始,它也是链接数组中的数字4,它指向字符数组中的字母B,依此类推。字符按字母顺序存储在一个新的数组中,我遇到的麻烦是在每一步之后得到字符数组的索引号,也许代码会显示我遇到麻烦的地方
INCLUDE Irvine32.inc
start = 1
.data
chars BYTE 'H','A','C','E','B','D','F','G'
links DWORD 0,4,5,6,2,3,7,0
array BYTE 0,0,0,0,0,0,0,0
.code
main PROC
mov al, chars +1
mov array, al
mov esi, start ; moves the start location into the esi register
mov eax, [links + 4] ; moves the second element of the array into eax
mov dl, chars[eax] ; moves the character element of the array chars into dl
mov array[esi], dl ; moves the character into the array
inc esi
mov eax, [links + 16]
mov dl, chars[eax]
mov array[esi], dl
inc esi
mov eax, [links + 8]
mov dl, chars[eax]
mov array[esi], dl
inc esi
mov eax, [links + 20]
mov dl, chars[eax]
mov array[esi], dl
inc esi
mov eax, [links + 12]
mov dl, chars[eax]
mov array[esi], dl
inc esi
mov eax, [links + 24]
mov dl, chars[eax]
mov array[esi], dl
inc esi
mov eax, [links + 28]
mov dl, chars[eax]
mov array[esi], dl
inc esi
main ENDP
END main
所以我想如果我知道如何在“链接”数组指向它之后获取数组元素的索引,我想我可以把它放到循环中,我只需要知道如何做到这一点。
答案 0 :(得分:2)
mov al, chars +1
mov array, al
mov esi, start ; moves the start location into the esi register
mov ebx, offset links
Again:
mov eax, [ebx + esi*4] ; moves the next element of the array into eax
mov dl, chars[eax] ; moves the character element of the array chars into dl
mov array[esi], dl ; moves the character into the array
inc esi
通过测试ESI寄存器,重复此代码所需的次数。
您可以通过从0开始而不是1来改进此代码。它将消除顶部的2行。它需要修改链接的定义。
links DWORD 1,4,5,6,2,3,7,0