Question

我有以下数据

SalId     EmpId   TakenSal  TakenDate       AvailSal        CompId
13        68       1000     02-Jul-2015     14000       1021
14        68       100      02-Jul-2015     13900       1021
15        69       1000     02-Jul-2015     11000       1021
16        82       1000     06-Jul-2015     9000        1024
17        82       1000     06-Jul-2015     8000        1024
18        83       1000     06-Jul-2015     9000        1024
19        83       1000     06-Jul-2015     8000        1024
20        82       1000     06-Jul-2015     7000        1024
21        82       1000     06-Jul-2015     6000        1024
22        82       1000     06-Jul-2015     5000        1024
23        82       1000     06-Jul-2015     4000        1024
24        94       1000     09-Jul-2015     9000        1014
25        94       1000     09-Jul-2015     8000        1014
26        94       1000     09-Jul-2015     7000        1014
27        94       1000     09-Jul-2015     6000        1014

我要在其中选择那些记录＆＃39; TakenDate＆＃39;离今天最近

我尝试过如下但是反感错误

select *
from Employee_SalaryDetails
where Employee_SalaryDetails.TakenDate = max(TakenDate)
group by Employee_SalaryDetails.EmpId
having count(Employee_SalaryDetails.EmpId)>0

Answer 1

我认为您正在寻找从今天开始的最近日期数据。

我已尝试过您的实际数据，

CREATE TABLE AbbasTable
(
    SalId         INT
   ,EmpId         INT
   ,TakenSal      INT
   ,TakenDate     date
   ,AvailSal      INT
   ,CompId        INT
)

insert into AbbasTable values (13, 68,  1000 ,       '02-Jul-2015',     14000  ,     1021)
insert into AbbasTable values (14, 68,  100  ,'02-Jul-2015',    13900,     1021)
insert into AbbasTable values (15,69 ,1000   ,'02-Jul-2015',    11000,     1021)
insert into AbbasTable values (16,82 ,1000   ,'06-Jul-2015',    9000 ,     1024)
insert into AbbasTable values (17,82 ,1000   ,'06-Jul-2015',    8000 ,     1024)
insert into AbbasTable values (18,83 ,1000   ,'06-Jul-2015',    9000 ,     1024)
insert into AbbasTable values (19,83 ,1000   ,'06-Jul-2015',    8000 ,     1024)
insert into AbbasTable values (20,82 ,1000   ,'06-Jul-2015',    7000 ,     1024)
insert into AbbasTable values (21,82 ,1000   ,'06-Jul-2015',    6000 ,     1024)
insert into AbbasTable values (22,82 ,1000   ,'06-Jul-2015',    5000 ,     1024)
insert into AbbasTable values (23,82 ,1000   ,'06-Jul-2015',    4000 ,     1024)
insert into AbbasTable values (24,94 ,1000   ,'09-Jul-2015',    9000 ,     1014)
insert into AbbasTable values (25,94 ,1000   ,'09-Jul-2015',    8000 ,     1014)
insert into AbbasTable values (26,94 ,1000   ,'09-Jul-2015',    7000 ,     1014)
insert into AbbasTable values (27,94 ,1000   ,'09-Jul-2015',    6000 ,     1014)

对于查询以下的输出用途，

WITH FianlTable
AS
(
    SELECT AT.*
          ,ROW_NUMBER() OVER(PARTITION BY empid ORDER BY takendate DESC) AS RN
    FROM   AbbasTable AT
)
SELECT *
FROM   FianlTable
WHERE  RN = 1
ORDER BY
       TakenDate DESC

SQL Fiddle Demo

Answer 2

如果表格中没有未来日期，只需返回最近的行（即“最接近今天的那些记录'TakenDate'）：

select *
from Employee_SalaryDetails
where TakenDate = (select max(TakenDate) from Employee_SalaryDetails)

Answer 3

如果您想要距离最近但在下方，可以使用

select esd1.*
from Employee_SalaryDetails AS esd1
where 
  esd1.TakenDate <= getdate()
  and not exists (select 1 
                  from Employee_SalaryDetails AS esd2
                  where esd2.TakenDate <= getdate()
                     and esd2.TakenDate > esd1.TakenDate )

如何获取距离今天最近的所有记录？

3 个答案: