在jquery tokenizer中解析json响应的错误

Question

我使用了来自https://www.zellerda.com/projects/jquery/tokenize的jquery multi select tokenizer jquery插件。我正在父母和老师之间开发一个PHP的邮件服务。当父类型为hrhername时，它需要进入下拉列表并点击它，它需要在文本框中。当我输入teachername时，控制台显示解析错误。当我检查响应时，我正在获取json数组。请帮助我。

Jquery的：

<link rel="stylesheet" type="text/css" href="../js/jquery_multipleSelect/jquery.tokenize.css" />
<script type="text/javascript" src="../js/jquery_multipleSelect/jquery.tokenize.js">
</script>

$('#to_message').tokenize({
    datas: "module/parents/communication/view_teacher_search.php?action=new_message",
    contentType: "application/json; charset=utf-8",//not working when commented
    //dataType: "json",//without commented also not working
    autosize: true,
    nbDropdownElements: 30,
    onAddToken: function(value, text, e){
        $( "#compose_message" ).append( '<input type="hidden" name="teacher_ids[]" id="'+value+'" value="'+value+'" >' );
    },
    onRemoveToken: function(value, e){
        $( "#"+value ).remove();
    }
});

view_teacher_search.php

 $db->query($getStudentsListQuery);
//$selStudents = '';
    while($row = $db->get_row())
   {                    
    $data .=   ' {
                    "text" : "' .$row[1] . ' - '. $row[2] .' - ['. $row[3] .']",
                    "value" : "'.$row[0].'"
                },';
    if($action == 'reply_message'){
        break;    
    }
   } 
  $new_userdata = substr_replace($data,"",-1); 
  echo '[ '. $new_userdata .' ]'; 

**编辑：**我是否需要在组件内进行响应？

Answer 1

问题是每个字面反斜杠需要使用另一个反斜杠

进行转义

\成为\\

"text" : "Abdul Hakim - Hamed - [Language and literature \\ Arabic]",