我在编程方面相当新，目前正在学习C＃。
我所拥有的是两个骰子随机滚动50卷 两个骰子总数加在一起，得出每个卷的总和。
我的问题是，如何创建一个频率表来计算在50个骰子结束时滚动某个数字的次数。
以下是我想要实现的目标。每个数字的计数图表（来自两个骰子）
1: |||
2: ||||
3: ||||||
4: |||||
5: ||||||||
6: ||
到目前为止，这是我的代码，
class Program
{
const int DICE_ROLLS = 51;
static void Main(string[] args)
{
Random random = new Random();
int[] firstDice = new int[DICE_ROLLS];
int[] secondDice = new int[DICE_ROLLS];
int diceSum = 0;
for (int roll = 1; roll <= 50; roll++)
{
firstDice[roll] = GenerateNumber(random);
secondDice[roll] = GenerateNumber(random);
diceSum = firstDice[roll] + secondDice[roll];
Console.WriteLine("ROLL {0}: {1} + {2} = {3}", roll, firstDice[roll], secondDice[roll], diceSum);
}
Console.WriteLine();
Console.WriteLine("~~~~~~~~~~~~~~~~");
Console.WriteLine("Number Frequency");
}
static int GenerateNumber (Random random)
{
return random.Next(1, 7);
}
}
答案 0 :(得分：0)
试试这个：
const int DICE_ROLLS = 51;
static void Main(string[] args)
{
Random random = new Random();
int[] firstDice = new int[DICE_ROLLS];
int[] secondDice = new int[DICE_ROLLS];
int[] count = new int[6];
int diceSum = 0;
for (int roll = 0; roll <= DICE_ROLLS - 1; roll++)
{
firstDice[roll] = GenerateNumber(random);
secondDice[roll] = GenerateNumber(random);
diceSum = firstDice[roll] + secondDice[roll];
Console.WriteLine("ROLL {0}: {1} + {2} = {3}", roll + 1, firstDice[roll], secondDice[roll], diceSum);
}
Console.WriteLine();
Console.WriteLine("~~~~~~~~~~~~~~~~");
Console.WriteLine("Number Frequency");
var allRolls = firstDice.Concat(secondDice).ToList();
for(var i = 1; i <= 6; i++)
{
Console.Write(i + ": ");
for(var j = 0; j < allRolls.Count(c => c == i); j++)
Console.Write("|");
Console.WriteLine();
}
}
static int GenerateNumber (Random random)
{
return random.Next(1, 7);
}
给出：
~~~~~~~~~~~~~~~~
Number Frequency
1: ||||||||||||||||||||
2: |||||||||||
3: ||||||||||||||||||
4: ||||||||||||||||
5: |||||||||||||||||||||
6: ||||||||||||||||
答案 1 :(得分：0)
假设有6个骰子，<script>
//constants
var Col = 20, Rows = 20;
var cellHeight = 25;
var cellWidth = 25;
var foodX;
var score;
var foodY;
var Nothing = 0, Snake = 1, Food = 2;
var Left = 37, Up = 38, Right = 39, Down = 40;
var canvas = document.getElementById('snakeCanvas');
var context = canvas.getContext('2d');
var dead = "false";
var snakeDirection = null;
var keystate;
var snake = [];
function start() //this is where we begin the long journey
{
init();
Tick();
}
function init() {
snake = [{ x: 5, y: 5 }];
snakeDirection = null;
score = 0;
document.getElementById("score").innerHTML = "Score: " + score;
setFood();
keystate = null;
}
function Tick() // just liker a timer tick
{
document.addEventListener("keydown", function (evt) {
keystate = evt.keyCode; // checks key presses
});
//document.addEventListener("keyup", function (evt) {
//delete keystate[evt.keyCode];
//});
update(); //after we check for a key press we update alllll the
stuff
setTimeout(Tick, 300);
//}
}
function update()
{
checkKey(); // checks what key has been pressed
for (var i = snake.length-1; i > 0; i--) {
snake[i].y = snake[i-1].y;
snake[i].x = snake[i-1].x
}
switch (snakeDirection) { // keys
case "DOWN":
snake[0].y++;
break;
case "UP":
snake[0].y--;
break;
case "RIGHT":
snake[0].x++;
break;
case "LEFT":
snake[0].x--;
break;
}
draw(); //draws all the stuff like food and snake
checkCollisions(); // self explaintory name
}
function checkKey() //Change the direction of the snake cant go
backwards too
{
if (keystate == Left && snakeDirection != "RIGHT" )
{
snakeDirection = "LEFT";
}
if (keystate == Up && snakeDirection != "DOWN")
{
snakeDirection = "UP";
}
if (keystate == Right && snakeDirection != "LEFT")
{
snakeDirection = "RIGHT";
}
if (keystate == Down && snakeDirection != "UP")
{
snakeDirection = "DOWN";
}
}
function setFood()
{ //WE ARE RUNNING OUT OF FOOD WE NEED NEW PROVISIONS
var next = "true"
do {
foodX = Math.floor((Math.random() * Rows));
foodY = Math.floor((Math.random() * Col));
for (var i = 0; i < snake.length; i++) { // IT SUCKS WHEN I
CANT EAT FOOD BECAUSE ITS ALREADY INSIDE OF ME
if (snake[i].x == foodX && snake[i].y == foodY) {
next = "false"
}
}
}
while (next == "false")
draw(); // Pretty pictures
}
function checkCollisions()
{
for (var i = 1; i < snake.length; i++) { // STOP hitting
yourself
if (snake[0].x == snake[i].x && snake[0].y == snake[i].y) {
init();
}
}
if (snake[0].y < 0 || snake[0].y > Rows || snake[0].x < 0 ||
snake[0].x > Col) // you are forbidon to veture from the canvas
{
init();
}
if (snake[0].x == foodX && snake[0].y == foodY) { //Yummy FOOD EAT
EAT EAT
score++;
document.getElementById("score").innerHTML = "Score: " + score;
setFood();
snake.push({ x: null, y: null }); // I got fatter
}
}
function draw()
{
context.clearRect(0, 0, canvas.width, canvas.height); // clears
canvas
context.fillStyle = "#FF0000"; // pretty colour for the head of
the snake
context.fillRect(snake[0].x * cellWidth, snake[0].y * cellWidth,
cellWidth, cellHeight);
context.fillStyle = "#09F";
for (var i = 1; i < snake.length; i++)
{
context.fillRect(snake[i].x * cellWidth, snake[i].y * cellWidth,
cellWidth, cellHeight);
}
context.fillStyle = "#F90"; // FOOD FOOD FOOD FOOD
context.fillRect(foodX * cellWidth, foodY * cellWidth, cellWidth,
cellHeight);
}
start(); // starts hence the name start
</script>
可能是一个不错的选择。
Dictionary您甚至可以通过基于变量（例如
）生成初始字典值，根据不同的骰子轻松自定义它var rolls = new SortedDictionary<int, int> { {1,0}, {2,0}, {3,0}, {4,0}, {5,0}, {6,0} };
for(int i = 0; i < 50; i++)
{
var first = Random.Next(1, 7);
var second = Random.Next(1, 7);
rolls[first]++;
rolls[second]++;
// Rest of rolling display code
}
// Header display code
foreach(var roll in rolls)
{
Console.Write("{0}: ", roll.Key);
for(int i = 0; i < rolls.Value; i++)
{
Console.Write("|");
}
Console.WriteLine();
}
您可以将int sides = 12;
var rolls = new SortedDictionary<int, int>();
foreach(var value in Enumerable.Range(1, sides))
{
rolls.Add(value, 0);
}
替换为Random.Next(1, 7)并使用一个非常通用的程序来掷骰子并计算其频率。
答案 2 :(得分：0)
这有效：
var rnd = new Random();
Console.WriteLine(
String.Join(
Environment.NewLine,
Enumerable
.Range(0, 50)
.Select(n => rnd.Next(1, 7))
.ToLookup(x => x)
.Select((xs, n) =>
String.Format("{0}: {1}", n + 1, new String('|', xs.Count())))));
我得到了这个（例如）：
1: |||||||
2: |||||||
3: |||||||||||
4: |||||||||
5: ||||||||
6: ||||||||