Question

我正在寻找一种使用SequelizeJS编写查询的方法，该方法包含一个引用多个模型（表）的OR子句。

我希望sql最终看起来像这样：

select *
from Department
inner join Office on Department.OfficeId = Office.Id
where Office.Name like 'spokane%'
or Department.Name like 'spokane%'

我已经看到有关过滤联接表的类似问题，答案如下所示。

options.include = [{
    model: offices.model,
    where: {
        name: {
           $like: 'spokane%'
        }
    }
  }];

options.where = Sequelize.or(
    {
       'name': {
          $like: 'spokane%'
        }
    });

departments.findAndCount(options);

然而，这并没有产生正确的sql。

它吐出这样的东西：

select *
from Department
inner join Office on Department.OfficeId = Office.Id and Office.name like 'spokane%'
where Department.name like 'spokane%'

非常感谢任何帮助。

Answer 1

options.where = {
  $or: [
    sequelize.where(sequelize.col('office.name'), { $like: 'foo'}),
    sequelize.where(sequelize.col('department.name'), { $like: 'foo'})
  ]
}

Sequelize OR子句有多个模型

1 个答案: