Question

在我的程序中，我使用Integer.parseInt（）从字符串创建了一个int 方法，现在我在计算中使用后必须打印一些东西但我收到错误。它会一直打印到直到特征为止的位置。

感谢任何帮助！

如果它有用，这是我得到的错误。粗体部分是程序在遇到错误之前打印的距离。

**你赢了：$ **线程“main”中的异常java.util.IllegalFormatConversionException：f！= java.lang.Integer at java.util.Formatter $ FormatSpecifier.failConversion（Formatter.java:4302） at java.util.Formatter $ FormatSpecifier.printFloat（Formatter.java:2806） at java.util.Formatter $ FormatSpecifier.print（Formatter.java:2753）在java.util.Formatter.format（Formatter.java:2520）在java.io.PrintStream.format（PrintStream.java:970）在java.io.PrintStream.printf（PrintStream.java:871）在SlotMachine.main（SlotMachine.java:50）

 //variables declared
    //BALANCE is declared as a constant
            String userBet, dollar, coins;
            int decimal, winnings, dollarToInt, coinsToInt, bet;
            int slot1, slot2, slot3;

    //changing users inputted string to int
            do {
                System.out.print("Enter your bet (or 0 to quit): $");
                userBet = kbd.nextLine();
                decimal = userBet.indexOf(".");
                dollar = userBet.substring(0, (decimal));
                coins = userBet.substring(decimal+1);
                dollarToInt = Integer.parseInt(dollar);
                coinsToInt = Integer.parseInt(coins);
                bet = (dollarToInt*100) + (coinsToInt);

//calculating winnings and new balance
            if (slot1 == slot2) {
                winnings = (slot1 * bet/2);
                System.out.printf("You have won: $%.2f\n", (winnings));
                System.out.printf("Balance: $%.2f\n\n", (winnings - bet + BALANCE));


                if (slot1 == slot3) {
                    winnings = (slot1 * bet/2);
                    System.out.printf("You have won: $%.2f\n", (winnings));
                    System.out.printf("Balance: $%.2f\n\n", (winnings - bet + BALANCE));

                }

                if (slot2 == slot3) {
                    winnings = (slot2 * bet/2);
                    System.out.printf("You have won: $%.2f\n", (winnings));
                    System.out.printf("Balance: $%.2f\n\n", (winnings - bet + BALANCE));
                }

Answer 1

您将int（奖金）格式化为Float（％.2f）。将Winnings更改为Float，或将其格式化为int。

我无法格式化我从parse方法创建的int。

1 个答案: