是否可以进行一次返回第二个表的值并将其他值设置为NULL的查询。我坚持这个。
这是我的查询
return $this->db->get_results(
"
SELECT id, name, type, check_in_days, check_out_days, all_check_out_days, minimum_stay, maximum_stay, all_accom, GROUP_CONCAT( accom_id ) as accom, GROUP_CONCAT( seasons_id ) as seasons, conditional_type
FROM $this->booking_rules_table
LEFT JOIN $this->booking_rules_accom_table
ON $this->booking_rules_table.id = $this->booking_rules_accom_table.rule_id
LEFT JOIN $this->booking_rules_seasons_table
ON $this->booking_rules_table.id = $this->booking_rules_seasons_table.rule_id
GROUP BY id
"
, ARRAY_A );
这将返回一个这样的数组
[2] => Array
(
[id] => 54
[name] =>
[type] => minimum_stay
[check_in_days] => 0,1,2,3,4,5,6
[check_out_days] => 0,1,2,3,4,5,6
[all_check_out_days] => 1
[minimum_stay] => 0
[maximum_stay] => 9999
[all_accom] => 0
[accom] => 7,7,7
[seasons] => 1,3,4
[conditional_type] => compulsory
)
你看到[住宿]返回7次,因为[季节]有3个值。
我可以用我的查询修复此问题,还是有其他解决方案。我不想爆炸它并再次构建阵列。