Question

我试图使用Mysqli代替Mysql与php，以便从我的数据库收集内容，下面的代码（代码1）工作正常，但我有2个问题：

1 - 代码1显示同一行上的所有行，而不是彼此之上的所有行。

2 - 我无法获得如何获取表的列名，就像我使用mysql方法（代码2）时那样。

--------------------- code 1 ----------------

double kinetic_energy(double mass, std::array<double,3> const&velocity)
{
  return 0.5 * mass * (square(velocity[0])+square(velocity[1])+square(velocity[2])); 
}

---------------- code 2 ------------

 <?php
    $db = new mysqli('localhost', 'root', '', '...');
    if($db->connect_errno > 0){
    die('Unable to connect to database [' . $db->connect_error . ']');
    }
    $sql = <<<SQL SELECT * FROM `...`
    SQL;

    if(!$result = $db->query($sql)){
        die('There was an error running the query [' . $db->error . ']');
    }
    while($row = $result->fetch_assoc()){
        echo "<tr class='info'>
                    <td>" . $row['...'] . "</td>
                    <td>" . $row['...'] . "</td>
                    <td>" . $row['...'] . "</td> 
                    </tr>";     }    ?>

------------修正更新------------------

addedd

<?php
$connection = mysql_connect('localhost', 'root', ''); 
mysql_select_db('dhocp');    
$query = "SELECT * FROM ..."; 
$result = mysql_query($query);
echo "<table class='table'>";
echo '<tr>';
for ($i = 0; $i < mysql_num_fields($result); $i++) { 
    echo "<th>".mysql_field_name($result, $i)."</th>"; 
}
echo '</tr>';
while($row = mysql_fetch_array($result)){   //Creates a loop to loop through results
echo "<tr class='info'><td>" . $row['...'] . "</td>
               <td>" . $row['...'] . "</td>
               <td>" . $row['...'] . "</td>
               </tr>"; 
}
echo "</table>"; 
mysql_close(); 
?>

在while循环之前的代码1中

------------修复更新2 --------------显示列表----

  echo "<table class='table'>";

Answer 1

你可以，例如在第一次迭代中打印数组键（=字段名称）

$header = true;
foreach( $mysqli->query('SELECT id,x,y FROM soFoo') as $row ) {
    if ( $header ) {
        // on the first iteration print the array-keys <-> field names
        $header = false;
        echo '<tr><th>', join('</th><th>', array_map('htmlspecialchars', array_keys($row))), '</th></tr>', "\r\n";
    }
    echo '<tr><td>', join('</td><td>', array_map('htmlspecialchars', $row)), '</th></tr>', "\r\n";
}

或者您按照http://docs.php.net/mysqli.quickstart.metadata

的描述获取元数据

$result = $mysqli->query('SELECT id,x,y FROM soFoo');
$meta = $result->fetch_fields();
echo '<tr><th>', join('</th><th>', array_map( function($e) { return htmlspecialchars($e->name); }, $meta)), '</th></tr>', "\r\n";

foreach( $result as $row ) {
    echo '<tr><td>', join('</td><td>', array_map('htmlspecialchars', $row)), '</th></tr>', "\r\n";
}

Mysqli显示一行中的表内容，并且未从db中检索列名

1 个答案: