Jira - 通过REST API获取问题评级

时间:2015-10-21 18:40:21

标签: rest jira jira-rest-api jira-agile

我正试图通过REST获得Jira ID的排名:

这是我发送的GET请求:

JIRA-HOST/rest/agile/1.0/issue/MyIssue

我正在获取密钥:customfield_10690,这是评级字段,但此字段的值不可读且不可解析,我得到的值是:"customfield_10690":"0|i1qu83:"

我该怎么办?

2 个答案:

答案 0 :(得分:0)

评级系统是一系列图像吗?喜欢明星什么的?也许jira试图将图像作为文本发送给你,这会成为无法打印的东西。

如果是这种情况,我认为你唯一的选择就是: 1.将评级系统更改为数字 2.如果值一致,请进行映射,以便映射" 0 | i1qu83:"评分对您的代码有意义。

答案 1 :(得分:0)

您看到的值是lexorank token

如果需要数字排名(例如,排名15在100中),则可能希望使用JQL(其有限的查询语言)通过JIRA搜索端点获取问题的总列表,并枚举结果或搜索问题在增加或更新某些等级编号时需要按键。如果您的查询返回多个结果,性能很重要,而您只需要一个问题,则可能要使用更智能的搜索,例如binary search

这是一个使用node client的粗略示例:

import jiraAPI from 'jira-client'

const jira = new jiraAPI({
  protocol: 'https',
  host: process.env['JIRA_HOST'],
  username: process.env['JIRA_USERNAME'],
  password: process.env['JIRA_PASSWORD'],
  apiVersion: '2',
  strictSSL: true,
  timeout: 30000, // 30s
})

const JQL = 'project = "your-project" AND status IN ("To Do", "In Progress", "Blocked") order by status desc, Rank asc'

const FIELDS = ['key', 'priority', 'status', 'summary', 'labels', 'assignee']

const formatIssue = ({ issue: { key, fields = {} }, rank = 0, total = 0 }) => ({
  key,
  rank,
  total,
  priority: fields.priority.name,
  status: fields.status.name,
  summary: fields.summary,
  assignee: fields.assignee ? fields.assignee.displayName : null,
  labels: fields.labels
})

async function* issueGenerator ({ offset = 0, limit = 100 }) {
  for (let max = 1; offset < max; offset += limit) {
    const { total = 0, maxResults = 0, startAt = 0, issues = [] } = await jira.searchJira(JQL, {
      startAt: offset,
      maxResults: limit,
      fields: FIELDS
    })

    max = total
    limit = maxResults
    offset = startAt

    for (let i = 0, len = issues.length; i < len; i++) {
      yield formatIssue({ issue: issues[i], rank: offset + i + 1, total })
    }
  }
}


async function fetchIssuesWithLabel (label) {
  const issueIterator = issueGenerator({ offset: 0, limit: 100 })
  const teamIssues = []

  for await (const issue of issueIterator) {
    if (issue.labels.includes(label)) {
      teamIssues.push(issue)
    }
  }

  return teamIssues
}

fetchIssuesWithLabel('bug').then(result => console.log(result))