我混合了scala-java spring-boot mvc项目。我正在尝试使用javax.validation.ConstraintValidator
实现请求bean的自定义验证器
我在这里阅读其他线程,最好在Java Does scala suport JSR-303 validation?
我在Java中编写了自定义Constraint注释,在scala中编写了ConstraintValidator类,但是当我指定@Constraint(validatedBy = ScalaCustomerValidator.class)时,它给出了Type mismatch: cannot convert from Class<ScalaCustomerValidator> to Class<? extends ConstraintValidator<?,?>>[]
的编译错误。我的ScalaCustomerValidator确实扩展了ConstraintValidator。
// java的
@Constraint(validatedBy = ScalaCustomerValidator.class) //Type mismatch error
@Target(value = ElementType.TYPE)
@Retention(RetentionPolicy.RUNTIME)
public @interface ScalaCustomerValid {
String message() default "Invalid tab to filter combination";
Class<?>[] groups() default {};
Class<? extends Payload>[] payload() default {};
}
// ConstraintValidator的scala定义
class ScalaCustomerValidator extends ConstraintValidator[ScalaCustomerValid, ScalaCustomer] { .. }
javap输出:
javap ScalaCustomerValidator
Warning: Binary file ScalaCustomerValidator contains com.ScalaCustomerValidator
Compiled from "ScalaCustomerValidator.scala"
public class com.ScalaCustomerValidator implements javax.validation.ConstraintValidator<com.ScalaCustomerValid, com.ScalaCustomer> {
public void initialize(com.ScalaCustomerValid);
public boolean isValid(com.ScalaCustomer, javax.validation.ConstraintValidatorContext);
public boolean isValid(java.lang.Object, javax.validation.ConstraintValidatorContext);
public void initialize(java.lang.annotation.Annotation);
public com.ScalaCustomerValidator();
}
答案 0 :(得分:1)
你的问题是由于不可能获得scala对象的类。 Scala编译器为对象ScalaCustomerValidator生成名为ScalaCustomerValidator $的类。 ScalaCustomerValidator $实际上实现了ConstraintValidator,并且没有办法引用它的类。 如果您尝试使用scala:
val cl = classOf[ScalaCustomerValidator]
你也会收到编译错误。