Question

我尝试创建基本号码查找游戏（1-100）。但总是在第二次尝试后程序终止。

代码：

Random rnd = new Random();
int rndm  = rnd.nextInt(100);

int tryn;
Scanner sc = new Scanner(System.in);
System.out.print("Guess: ");
tryn = sc.nextInt();

if (tryn == rndm) {
        System.out.println("You win.");
        sc.close();
    }
    else if (tryn > rndm) {
        System.out.println("Too high.");
        System.out.print("Guess again: ");
        tryn = sc.nextInt();
    }
    else {
        System.out.println("Too low.");
        System.out.print("Guess again: ");
        tryn = sc.nextInt();    
    }

当我运行输出时：

<terminated> test2 [Java Application]...
Guess: 30
Too low.
Guess again: 50

为什么我的程序没有循环？谢谢你的帮助。

Answer 1

在代码中添加循环...

while(tryn != rndm){

Answer 2

请参阅以下代码（我已测试过）：

import java.util.Random;
import java.util.Scanner;

public class Guess {

    public static void main(String[] args) {
        Random rnd = new Random();
        int rndm = rnd.nextInt(100);

        int tryn;
        Scanner sc = new Scanner(System.in);
        System.out.print("Guess: ");

        while (sc.hasNextInt()) {
            tryn = sc.nextInt();

            if (tryn == rndm) {
                System.out.println("You win.");
                break;
            } else if (tryn > rndm) {
                System.out.println("Too high.");
                System.out.print("Guess again: ");
            } else {
                System.out.println("Too low.");
                System.out.print("Guess again: ");
            }
        }

        sc.close();
    }
}

Java if语句终止错误

2 个答案: