Question

我有一个样本json数据，如：

{
  "phone_number": "780-414-2085",
  "city": "Edmonton",
  "updated": "2015-10-19T00:03:10",
  "name": "Sir William Place ",
  "url": "http://www.bwalk.com/en-CA/Rent/Details/Alberta/Edmonton/Sir-William-Place",
  "last_visited": "2015-10-19T00:03:10",
  "rooms": [{
    "available": "Available",
    "bathrooms": ["1"],
    "suite_type": "1 Bedroom",
    "square_feet": ["594", "649"],
    "deposit": ["$499"],
    "price_range": ["$1059", "$1209"]
  }, {
    "available": "Available",
    "bathrooms": ["1"],
    "suite_type": "1 Bedroom + Den",
    "square_feet": ["771"],
    "deposit": ["$499"],
    "price_range": ["$1169", "$1249"]
  }, {
    "available": "Available",
    "bathrooms": ["1", "2"],
    "suite_type": "2 Bedroom",
    "square_feet": ["894", "970"],
    "deposit": ["$499"],
    "price_range": ["$1344", "$1494"]
  }, {
    "available": "Available",
    "bathrooms": ["2"],
    "deal": ["October FREE and $299 Security Deposit on 12 month leases "],
"suite_type": "2 Bedroom Bi-level",
"square_feet": ["894"],
"deposit": ["$499"],
"price_range": ["$1344", "$1394"]
  }, {
    "available": "Waiting List",
    "bathrooms": ["1"],
    "suite_type": "Bachelor",
    "square_feet": ["540"],
    "deposit": ["$499"],
    "price_range": ["$1004", "$1054"]
  }],
  "address": "8830-85 St., Edmonton, Alberta, T6C 3C3",
  "zip_code": "T6C 3C3"
}

我正在运行一个jq表达式，如：

'{phone_number, city, updated, name, address, zip_code, url, last_visited} + (.rooms[] | {suite_type, price_range_start: .price_range[0], price_range_end: .price_range[1]} + {available, square_foot_start:.square_feet[0], square_foot_end:.square_feet[1], deposit:.deposit[0], bathrooms:.bathrooms[0]})'

这给了我一个ok输出但重复相同的名称，因为我只列出了rooms数组。我希望能够将房间数组中的每个项目设置为类似room1，room2，room3等的东西。但是也要将它保存在一个条目中，所以例如这里的示例最终有5个条目，因为有5个房间和例如，名称重复5次，因为我现在设置它的方式。我想我需要将房间映射到某些东西，但不知道该怎么做。

有人可以就如何做到这一点提出建议吗？

Answer 1

您可以更新数组中的元素，同时保留其他元素，如下所示：

'.rooms[] |=  {suite_type, price_range_start: .price_range[0],
  price_range_end: .price_range[1]} + {available,
  square_foot_start:.square_feet[0], square_foot_end:.square_feet[1],
  deposit:.deposit[0], bathrooms:.bathrooms[0]}'

Answer 2

这是一个使用函数的解决方案。

def common_columns:
   "phone_number", "city", "updated", "name", "address", "zip_code", "url", "last_visited"
;
def common:
   .phone_number, .city, .updated, .name, .address, .zip_code, .url, .last_visited
;
def room_columns(n):
     range(n)
   | (
      "available_\(.)", "bathrooms_\(.)", "suite_type_\(.)",
      "square_feet_start_\(.)", "square_feet_end_\(.)", "deposit_\(.)",
      "price_range_start_\(.)", "price_range_end_\(.)"
     )
;
def rooms(n):
     . as $r
   | range(n)
   | $r.rooms[.]
   | (
       .available, .bathrooms[0], .suite_type,
       .square_feet[0,1], .deposit[0], .price_range[0,1]
     )
;

  [ common_columns, room_columns(6) ]
, [ common,         rooms(6) ]
| @csv

您可以将6更改为您需要的多组房间列。

JQ数组到新字段

2 个答案: