Question

我有一个小型的中间件，我想为它编写一个测试..我想做两个测试：

模拟role_id与1;句柄应返回TRUE
模拟role_id 2;句柄应该返回FALSE

如何做到这一点？

namespace App\Http\Middleware;

use Closure;
use Auth;
use Redirect;

class RedirectIfNotAdminUser {

    /**
     * Handle an incoming request.
     *
     * @param  \Illuminate\Http\Request  $request
     * @param  \Closure  $next
     * @return mixed
     */
    public function handle($request, Closure $next) {
        if (Auth::user()->role_id != config('Roles.admin')) {
            return Redirect::action('Auth\AuthController@getLogin');
        }

        return $next($request);
    }

}

目前我运行的测试如下：

public function testIsAdminUser() {
    $user = factory(App\User::class)->make(['role_id' => '1']); 

    $this->be($user);

    $response = $this->action('GET', 'admin\DashboardController@index');

    $this->assertEquals(200, $response->getStatusCode());
}

我还必须在设置中添加一行，没有它$ this-＆gt; be（）不起作用

public function setUp() { 
    $this->refreshApplication();
}

他们是更好的方法吗？

Answer 1

试试这个：

public function setUp()
{
    $this->redirectIfNotAdminUser = new App\Http\Middleware\RedirectIfNotAdminUser;
}

public function testIsAdminUser()
{
    // create a $user object (using a factory or something else).
    // assuming $user has a property role_id = 1.
    $this->actingAs($user);

    // create a mock of $request and $next.
    $response = $this->redirectIfNotAdminUser->handle($request, $next);

    $this->assertEquals(200, $response->getStatusCode());
}

public function testIsNotAdminUser()
{
    // create a $user object (using a factory or something else).
    // assuming $user has a property role_id = 2.
    $this->actingAs($user);

    // create a mock of $request and $next.
    $response = $this->redirectIfNotAdminUser->handle($request, $next);

    $this->assertEquals(302, $response->getStatusCode());
}

我相信中间件会返回状态代码为200的响应，如果它是OK和302，则会返回。

请记住，您将成为创建User实例并让其登录的人（使用actingAs()方法）并且您将成为创建模拟人员的人$request和$next将传递给您的中间件handle()方法。

Larave5中的UnitTest中间件

1 个答案: