我关注Force directed Graph。如何防止力导向图中链接（线）的重叠。预期的输出应该是这样的 this。当前的JSON数据不包含任何父子关系。
这是我的代码：
var width = 960,
height = 500;
var color = d3.scale.category20();
var force = d3.layout.force()
.charge(-120)
.linkDistance(30)
.size([width, height]);
var svg = d3.select("body").append("svg")
.attr("width", width)
.attr("height", height);
var graph = {
"nodes":[
{"name":"Myriel","group":1},
{"name":"Napoleon","group":1},
{"name":"Mlle.Baptistine","group":1},
{"name":"Mme.Magloire","group":1},
{"name":"CountessdeLo","group":1},
{"name":"Geborand","group":1},
{"name":"Champtercier","group":1},
{"name":"Cravatte","group":1},
{"name":"Count","group":1},
{"name":"OldMan","group":1},
{"name":"Labarre","group":2},
{"name":"Valjean","group":2},
{"name":"Marguerite","group":3},
{"name":"Mme.deR","group":2},
{"name":"Isabeau","group":2},
{"name":"Gervais","group":2},
{"name":"Tholomyes","group":3},
{"name":"Listolier","group":3},
{"name":"Fameuil","group":3},
{"name":"Blacheville","group":3},
{"name":"Favourite","group":3},
{"name":"Dahlia","group":3},
{"name":"Zephine","group":3},
{"name":"Fantine","group":3},
{"name":"Mme.Thenardier","group":4},
{"name":"Thenardier","group":4},
{"name":"Cosette","group":5},
{"name":"Javert","group":4},
{"name":"Fauchelevent","group":0},
{"name":"Bamatabois","group":2},
{"name":"Perpetue","group":3},
{"name":"Simplice","group":2},
{"name":"Scaufflaire","group":2},
{"name":"Woman1","group":2},
{"name":"Judge","group":2},
{"name":"Champmathieu","group":2},
{"name":"Brevet","group":2},
{"name":"Chenildieu","group":2},
{"name":"Cochepaille","group":2},
{"name":"Pontmercy","group":4},
{"name":"Boulatruelle","group":6},
{"name":"Eponine","group":4},
{"name":"Anzelma","group":4},
{"name":"Woman2","group":5},
{"name":"MotherInnocent","group":0},
{"name":"Gribier","group":0},
{"name":"Jondrette","group":7},
{"name":"Mme.Burgon","group":7},
{"name":"Gavroche","group":8},
{"name":"Gillenormand","group":5},
{"name":"Magnon","group":5},
{"name":"Mlle.Gillenormand","group":5},
{"name":"Mme.Pontmercy","group":5},
{"name":"Mlle.Vaubois","group":5},
{"name":"Lt.Gillenormand","group":5},
{"name":"Marius","group":8},
{"name":"BaronessT","group":5},
{"name":"Mabeuf","group":8},
{"name":"Enjolras","group":8},
{"name":"Combeferre","group":8},
{"name":"Prouvaire","group":8},
{"name":"Feuilly","group":8},
{"name":"Courfeyrac","group":8},
{"name":"Bahorel","group":8},
{"name":"Bossuet","group":8},
{"name":"Joly","group":8},
{"name":"Grantaire","group":8},
{"name":"MotherPlutarch","group":9},
{"name":"Gueulemer","group":4},
{"name":"Babet","group":4},
{"name":"Claquesous","group":4},
{"name":"Montparnasse","group":4},
{"name":"Toussaint","group":5},
{"name":"Child1","group":10},
{"name":"Child2","group":10},
{"name":"Brujon","group":4},
{"name":"Mme.Hucheloup","group":8}
],
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]
}
//d3.json("miserables.json", function(error, graph) {
force
.nodes(graph.nodes)
.links(graph.links)
.start();
var link = svg.selectAll(".link")
.data(graph.links)
.enter().append("line")
.attr("class", "link")
.style("stroke-width", function(d) { return Math.sqrt(d.value); });
var node = svg.selectAll(".node")
.data(graph.nodes)
.enter().append("circle")
.attr("class", "node")
.attr("r", 5)
.style("fill", function(d) { return color(d.group); })
.call(force.drag);
node.append("title")
.text(function(d) { return d.name; });
force.on("tick", function() {
link.attr("x1", function(d) { return d.source.x; })
.attr("y1", function(d) { return d.source.y; })
.attr("x2", function(d) { return d.target.x; })
.attr("y2", function(d) { return d.target.y; });
node.attr("cx", function(d) { return d.x; })
.attr("cy", function(d) { return d.y; });
});
//});.node {
stroke: #fff;
stroke-width: 1.5px;
}
.link {
stroke: #999;
stroke-opacity: .6;
}<script src="https://cdnjs.cloudflare.com/ajax/libs/d3/3.4.0/d3.min.js"></script>
答案 0 :(得分：1)
如果通过重叠意味着两个节点之间存在多个链接，则可以通过将它们绘制为曲率增加的弧来解析它们，从而在视觉上将它们分开。
如果通过重叠意味着边缘交叉，那么只有当你的图形是平面的时候才有可能 - https://en.wikipedia.org/wiki/Planarity_testing - 并且看你的图形不是 - 它至少有2个子图，几乎完全连通。你需要一个专门试图减少边缘交叉的图形布局算法，坏消息是它是一个NP完全问题
交叉号码是NP-Complete：DOI：10.1137 / 0604033 https://en.wikipedia.org/wiki/Crossing_number_(graph_theory)
通过用汇合的边缘或图案替换它们的边缘集，可以在完整的子图上使用一些技术，但这是步入图绘制研究：没有简单的答案
汇合图纸：以平面方式显示非平面图 DOI：10.1007 / 978-3-540-24595-7_1
Motif简化：改善网络可视化 Fan，Connector和Clique字形的可读性 DOI：10.1145 / 2470654.2466444
简而言之，唯一可以保证不进行边缘交叉的方法不是绘制边缘。也许尝试查看图形的矩阵式可视化？ - https://bost.ocks.org/mike/miserables/
答案 1 :(得分：0)
我想发表评论，但我没有足够的声誉，所以我在回答＆＃34;相反 - 抱歉，这不是一个很好的答案...
您的预期输出示例是树/非循环，它或多或少地神奇地解决了重叠链接的问题。你可以在这个例子中看到Mike Bostock（http://bl.ocks.org/mbostock/1062288），通过数据为树，没有多少链接重叠。
所以......
如果您的数据是树，您可能会很幸运，链接重叠可能不是问题。您会注意到，当兄弟节点具有不同的链接距离（导致侄女/侄子 - 阿姨/叔叔链接重叠）时，Bostock示例中的重叠发生。控制链接距离（可能使它们成为树深度的函数，在根部附近有更长的链接），我认为将防止树中的任何重叠。
如果你的数据有周期（比如悲惨世界的数据），防止重叠就会复杂得多，并且不会让自己排序。就像其他人说的那样，我认为任何D3布局都不可能。