来自本地文件系统的Ap​​ache httpclient GET文件？

Question

我总是认为这应该是可能的：

val client = HttpClients.createDefault()
val httpGet = new HttpGet("file:///Users/user01/testfile")
client.execute(httpGet)

抛出：

client: org.apache.http.impl.client.CloseableHttpClient = org.apache.http.impl.client.InternalHttpClient@4ba3987b
httpGet: org.apache.http.client.methods.HttpGet = GET file:///Users/user01/testfile HTTP/1.1
org.apache.http.client.ClientProtocolException: URI does not specify a valid host name: file:///Users/user01/testfile
    at org.apache.http.impl.client.CloseableHttpClient.determineTarget(test_ws.sc0.tmp:90)
    at org.apache.http.impl.client.CloseableHttpClient.execute(test_ws.sc0.tmp:78)
    at org.apache.http.impl.client.CloseableHttpClient.execute(test_ws.sc0.tmp:103)
    at #worksheet#.#worksheet#(test_ws.sc0.tmp:6)

当我创建HttpGet实例时，哪种有意义。

有人知道如何做到这一点吗？

Answer 1

令人惊讶的是，HttpClient是一个客户端HTTP传输库。它不支持任何其他传输协议。甚至不是本地文件系统。你可能想要的是Apache Commons VFS或类似的东西。

Answer 2

HttpClient实际上仅用于HTTP，但是您可以使用普通Java来实现相同的目的：

try (BufferedInputStream in = new BufferedInputStream(new URL("file:///tmp/test.in").openStream());
     FileOutputStream fileOutputStream = new FileOutputStream(new File("/tmp/test.out"))){
    byte dataBuffer[] = new byte[1024];
    int bytesRead;
    while ((bytesRead = in.read(dataBuffer, 0, 1024)) != -1) {
        fileOutputStream.write(dataBuffer, 0, bytesRead);
    }
} catch(IOException e){
    e.printStackTrace();
}

Answer 3

使用内置的java.net.URL类怎么样？它处理http和文件协议。