Question

我使用谷歌地图检测当前的地方，但得到错误这是我的代码：

private void initGoogleApiClient() {
    mGoogleApiClient = new GoogleApiClient
            .Builder(this)
            .enableAutoManage(this, 0, new GoogleApiClient.OnConnectionFailedListener() {
                @Override
                public void onConnectionFailed(ConnectionResult connectionResult) {

                }
            })
            .addApi(Places.GEO_DATA_API)
            .addApi(Places.PLACE_DETECTION_API)
            .addConnectionCallbacks(new GoogleApiClient.ConnectionCallbacks() {
                @Override
                public void onConnected(Bundle bundle) {
                    guessCurrentPlace();
                }

                @Override
                public void onConnectionSuspended(int i) {

                }
            })
            .addOnConnectionFailedListener(new GoogleApiClient.OnConnectionFailedListener() {
                @Override
                public void onConnectionFailed(ConnectionResult connectionResult) {

                }
            })
            .build();
}


private void guessCurrentPlace() {
    PendingResult<PlaceLikelihoodBuffer> result =
            Places.PlaceDetectionApi.getCurrentPlace(mGoogleApiClient, null);
    result.setResultCallback(new ResultCallback<PlaceLikelihoodBuffer>() {
        @Override
        public void onResult(PlaceLikelihoodBuffer likelyPlaces) {
            if (!likelyPlaces.getStatus().isSuccess()) {
                // Request did not complete successfully
                GooglePlayServicesUtil.getErrorDialog(
                        likelyPlaces.getStatus().getStatusCode(), ServiceProviderActivity.this ,0).show();
                Logger.d(TAG, "Place query did not complete. Error: " + likelyPlaces.getStatus().toString());
                likelyPlaces.release();
                return;
            }
            PlaceLikelihood placeLikelihood = likelyPlaces.get(0);
            String content = "";
            if (placeLikelihood != null && placeLikelihood.getPlace() != null &&
                    !TextUtils.isEmpty(placeLikelihood.getPlace().getName())) {
                content = "Most likely place: " + placeLikelihood.getPlace().getName() + "\n";
            }
            if (placeLikelihood != null) {
                content += "Percent change of being there: " + (int) (placeLikelihood.getLikelihood() * 100) + "%";
            }
            likelyPlaces.release();
        }
    });
}

我总是得到错误，而且MaybePlaces的值是： {status = Status {statusCode = INTERNAL_ERROR，resolution = null}，attributions = null}

我在AndroidManifest.xml中添加了这些

    <meta-data
        android:name="com.google.android.geo.API_KEY"
        android:value="key" />
    <meta-data
        android:name="com.google.android.gms.version"
        android:value="@integer/google_play_services_version" />

和

<!-- PlacePicker also requires OpenGL ES version 2 -->
<uses-feature
    android:glEsVersion="0x00020000"
    android:required="true" />

和其他使用权限。有谁知道为什么？

EDIT1：在Google Developer Console中，我获取了API的统计数据，显示所有响应都是“客户端错误（4XX）”

EDIT2：我的错误，使用release keystore生成KEY，但使用debug keystore调试。问题解决了。

Answer 1

我遇到了同样的问题，Place Detection API正在返回INTERNAL_ERROR，我后来发现这是因为Android中的新权限。

我请求了许可，但它确实有效。我希望它的帮助

if (ContextCompat.checkSelfPermission(this, Manifest.permission.ACCESS_FINE_LOCATION) != PackageManager.PERMISSION_GRANTED) {
     ActivityCompat.requestPermissions( this, new String[] { Android.Manifest.permission.ACCESS_COARSE_LOCATION  }, 2 );
}

使用PlaceDetectionApi检测地点获取INTERNAL_ERROR

1 个答案: