如何创建这样的列表:
$ap | ? { $_.observability_Analysis -eq "1.00000000000000E+00" } | select -expand Offset_Angle | % { [float]$_ }
$ap | ? { $_.observability_Analysis -eq "1.00000000000000E+00" } | % { [float]$_.Offset_Angle }
如果我写["a","a","a",... (repeating "a" a hundred times") "b","b","b",(repeating "b" a hundred times.. )]
,那么我会得到["a","b"] * 100
,这不是我想要的。
有没有像这个一样简单的功能,但是给了我想要的结果?
答案 0 :(得分:5)
只需将乘法第一和第二个元素生成的两个列表相加:
['a']*100 + ['b']*100
它比列表理解和排序更快:
python -m timeit "sorted(['a', 'b']*100)"
100000 loops, best of 3: 9.76 usec per loop
python -m timeit "[x for x in ['a', 'b'] for y in range(100)]"
100000 loops, best of 3: 5.15 usec per loop
python -m timeit "['a']*100 + ['b']*100"
1000000 loops, best of 3: 1.86 usec per loop
答案 1 :(得分:3)
没有
localhost:8080
答案 2 :(得分:1)
sak = ['a','b','c','d']
list = sak*100
print sorted(list)
var = ['a','b']
list = sorted(var*100)
答案 3 :(得分:0)
from itertools import repeat
list(repeat('a',100)) + list(repeat('b',100))