Question

如何在switch语句中乘以百分比和用户输入数字？我正在制作一个程序，它接受一些用户输入并以各种方式改变它，但我仍然坚持百分比部分。

int userChoice; //The user's choice from the menu.

double percentCurve = .1; //A 10% increase to the user's grade the user chooses by selecting option 2.

int userExtraPercent; //The percentage the user chooses to add to their grade by choosing option 4.
        userChoice = keyboard.nextInt ();

switch( userChoice) {

case 2:
System.out.println("Curve applied: " + percentCurve);
double adjustedGradeTwo = userGrade * percentCurve;
                System.out.println("Adjusted grade: " + adjustedGradeTwo);
                break;
                //Takes user's grade and adds 10 percent.

case 4:
System.out.println("Enter the percentage of the curve: "); 
userExtraPercent = keyboard.nextInt ();
System.out.println("Curve applied: " + userExtraPercent + "%"); 

int adjustedGradeFour = userGrade * userExtraPercent;
System.out.println("Adjusted grade: " + adjustedGradeFour); 
break;
//Adds a percentage chosen by the user to their initial grade.
}

我的switch语句中还有其他三种可能的选择，但我编辑了这些，因为它们正在工作，甚至我感到困惑，我写了一些血腥的东西。 XD

无论如何，我需要弄清楚的是如何获取用户的号码，将其转换为百分比，乘以用户的等级并将结果显示给用户。 IE，用户的等级为85，他们想要额外的12％，我的程序给他们95.2的等级。

Answer 1

这样的事情适用于案例4：

System.out.println("Enter the percentage of the curve: "); 
double userExtraPercent = keyboard.nextDouble();

double adjustedGradeFour = userGrade + (userGrade * (userExtraPercent / 100.0));
System.out.println("Curve applied: " + userExtraPercent + "%"); 
System.out.println("Adjusted grade: " + adjustedGradeFour);

使用Scanner.nextDouble，然后将其除以100（假设他们以12％的比例输入12）。

切换语句和百分比

1 个答案: