Answer 1

Answer 2

您必须在每次迭代中将所有字符移至屏幕右侧。您可以为此使用memmove。

1. create a buffer of the required size based on the horizontal space in the screen 
2.print required the number of '\n' to go to the bottom of the screen
    while(1)
    {
        3.add appropriate delay
        4./*use memmove to shift all the char to right side of screen*/
        memmove(buffer+1, buffer, horizondal_size - 2);

        5.add the new character to the starting of the buffer. add '\0' to the last position in the buffer (horizondal_size - 1)

        6./*print the buffer with carriage return, then  flush the output*/
        printf("%s\r",buffer);
        fflush(stdout);

}

Answer 3

Answer 4

Answer 5

Answer 6

这可行。

    #include <stdio.h>
    #include <conio.h>
    #include <string.h>
     //library for sleep() function
    #include <unistd.h>

    void main()
    {
     int i,j,n,k;

    //text to be srolled
     char t[30]="akhil is a bad boy";
     n=strlen(t);
     for(i=0;i<n;i++)
     {
        printf("\n");
//loop for printing spaces
        for(j=20-i;j>0;j--)
        {
            printf(" ");
        }

/*printing text by adding a character every time*/
        for(k=0;k<=i;k++)
        {
            printf("%c",t[k]);
        }
// clearing screen after every iteration
        sleep(1);
        if(i!=n-1)
        clrscr();

     }


    }