我在我的项目中使用VichUploaderBundle
我无法获取下载链接(使用vich_file
表单类型时)以考虑环境(特别是 dev )。我想要通过函数路由下载功能。
我的配置就像;
vich_uploader:
db_driver: orm
twig: true
mappings:
logo_image:
uri_prefix: /foo/image
upload_destination: %kernel.root_dir%/../app/private/images
inject_on_load: false
delete_on_update: true
delete_on_remove: true
无论环境如何,这都会生成http://example.com/foo/image/fubar.jpg
的下载uri
在开发环境中,它应该是http://example.com/app_dev.php/foo/image/fubar.jpg
,或者在测试环境中
http://example.com/app_test.php/foo/image/fubar.jpg
答案 0 :(得分:0)
一种可能的解决方案是使用可以访问路由器类的自定义文件名称类。
在配置中将uri_prefix
设置为 /
vich_uploader:
db_driver: orm
twig: true
mappings:
logo_image:
uri_prefix: /
upload_destination: %kernel.root_dir%/../app/private/images
inject_on_load: false
delete_on_update: true
delete_on_remove: true
namer: my.namer.foo
创建一个服务名称类,返回包含所需路径的完整URL(带参数);
<?php
namespace AppBundle\Service;
use Vich\UploaderBundle\Naming\NamerInterface,
Vich\UploaderBundle\Mapping\PropertyMapping;
use Symfony\Bundle\FrameworkBundle\Routing\Router;
class MyNamer implements NamerInterface
{
private $router;
public function __construct(Router $router)
{
$this->router = $router;
}
public function name($foo, PropertyMapping $mapping)
{
$router = $this->router->getContext();
$full_url = $router->getHost();
$full_url .= $router->getBaseUrl().'/';
$full_url .= 'foo/logo/'.strtolower($foo->getName());
return $full_url;
}
}
将其注册为服务;
services:
my.namer.foo:
class: AppBundle\Service\MyNamer
arguments: ['@router']
tags:
- { name: namer }