是否可以在matplotlib的图形窗口中选择一个区域来指定值,比如0?例如,我想说我想编写一个脚本,在某个点上,在图形窗口(pyplot.imshow)中显示图像,并要求用户选择一个值为0的区域? 希望这很清楚。
答案 0 :(得分:2)
这很有效。在这里你有一个pcolormesh
,你可以在其中点击,捕获click事件的onclick
函数将处理它并将所选方块设置为零。 mpl_connect
函数将onclick
函数连接到button_press_event
事件。您可以在点击后直接看到更新。
import numpy as np
import pylab as pl
pl.ioff()
rand_field = np.random.rand(10,10)
fig = pl.figure()
cm = pl.pcolormesh(rand_field, vmin=0, vmax=1)
pl.colorbar()
def onclick(event):
indexx = int(event.xdata)
indexy = int(event.ydata)
print("Index ({0},{1}) will be set to zero".format(indexx, indexy))
rand_field[indexy, indexx] = 0.
cm.set_array(rand_field.ravel())
event.canvas.draw()
cid = fig.canvas.mpl_connect('button_press_event', onclick)
pl.show()
在这里,您可以找到更高级的版本,可以拖动区域并处理错误,以防有人在图中外部点击。我把矩形的图画留给你了:
import numpy as np
import pylab as pl
pl.ioff()
rand_field = np.random.rand(10,10)
fig = pl.figure()
cm = pl.pcolormesh(rand_field, vmin=0, vmax=1)
pl.colorbar()
x_press = None
y_press = None
def onpress(event):
global x_press, y_press
x_press = int(event.xdata) if (event.xdata != None) else None
y_press = int(event.ydata) if (event.ydata != None) else None
def onrelease(event):
global x_press, y_press
x_release = int(event.xdata) if (event.xdata != None) else None
y_release = int(event.ydata) if (event.ydata != None) else None
if (x_press != None and y_press != None and x_release != None and y_release != None):
(xs, xe) = (x_press, x_release+1) if (x_press <= x_release) else (x_release, x_press+1)
(ys, ye) = (y_press, y_release+1) if (y_press <= y_release) else (y_release, y_press+1)
print("Slice [{0}:{1},{2}:{3}] will be set to zero".format(xs, xe, ys, ye))
rand_field[ys:ye, xs:xe] = 0.
cm.set_array(rand_field.ravel())
event.canvas.draw()
x_press = None
y_press = None
cid_press = fig.canvas.mpl_connect('button_press_event' , onpress )
cid_release = fig.canvas.mpl_connect('button_release_event', onrelease)
pl.show()