我试图通过使用用户名和密码解析登录URL来获取JSON数据。我尝试使用下面的代码,但我无法得到任何回复。请帮帮我。
我正在使用HTTP流程和API级别23。
我需要解析我的网址并获得以下回复
{
"response":{
"Team":"A",
"Name":"Sonu",
"Class":"First",
},
"Result":"Good",
}
在我的代码下面:
public class LoginActivity extends Activity {
JSONParser jsonparser = new JSONParser();
TextView tv;
String ab;
JSONObject jobj = null;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.login);
new retrievedata().execute();
}
class retrievedata extends AsyncTask<String, String, String>{
@Override
protected String doInBackground(String... arg0) {
// TODO Auto-generated method stub
jobj = jsonparser.makeHttpRequest("http://myurlhere.com");
// check your log for json response
Log.d("Login attempt", jobj.toString());
try {
ab = jobj.getString("title");
} catch (JSONException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return ab;
}
protected void onPostExecute(String ab){
tv.setText(ab);
}
}
}
答案 0 :(得分:42)
轻松获取JSON,特别是 Android SDK 23 :
public class MainActivity extends AppCompatActivity {
Button btnHit;
TextView txtJson;
ProgressDialog pd;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
btnHit = (Button) findViewById(R.id.btnHit);
txtJson = (TextView) findViewById(R.id.tvJsonItem);
btnHit.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
new JsonTask().execute("Url address here");
}
});
}
private class JsonTask extends AsyncTask<String, String, String> {
protected void onPreExecute() {
super.onPreExecute();
pd = new ProgressDialog(MainActivity.this);
pd.setMessage("Please wait");
pd.setCancelable(false);
pd.show();
}
protected String doInBackground(String... params) {
HttpURLConnection connection = null;
BufferedReader reader = null;
try {
URL url = new URL(params[0]);
connection = (HttpURLConnection) url.openConnection();
connection.connect();
InputStream stream = connection.getInputStream();
reader = new BufferedReader(new InputStreamReader(stream));
StringBuffer buffer = new StringBuffer();
String line = "";
while ((line = reader.readLine()) != null) {
buffer.append(line+"\n");
Log.d("Response: ", "> " + line); //here u ll get whole response...... :-)
}
return buffer.toString();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
if (connection != null) {
connection.disconnect();
}
try {
if (reader != null) {
reader.close();
}
} catch (IOException e) {
e.printStackTrace();
}
}
return null;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if (pd.isShowing()){
pd.dismiss();
}
txtJson.setText(result);
}
}
}
答案 1 :(得分:5)
我感到沮丧。
Android疯狂支离破碎,搜索时网络上不同数量的例子无济于事。
那就是说,我刚刚完成了部分基于mustafasevgi样本的样本, 部分由其他几个stackoverflow答案构建,我尝试以最简单的方式实现此功能,我觉得这很接近目标。
(请注意,代码应该易于阅读和调整,因此它不能完全适合您的json对象,但应该非常容易编辑,以适应任何情况)
protected class yourDataTask extends AsyncTask<Void, Void, JSONObject>
{
@Override
protected JSONObject doInBackground(Void... params)
{
String str="http://your.domain.here/yourSubMethod";
URLConnection urlConn = null;
BufferedReader bufferedReader = null;
try
{
URL url = new URL(str);
urlConn = url.openConnection();
bufferedReader = new BufferedReader(new InputStreamReader(urlConn.getInputStream()));
StringBuffer stringBuffer = new StringBuffer();
String line;
while ((line = bufferedReader.readLine()) != null)
{
stringBuffer.append(line);
}
return new JSONObject(stringBuffer.toString());
}
catch(Exception ex)
{
Log.e("App", "yourDataTask", ex);
return null;
}
finally
{
if(bufferedReader != null)
{
try {
bufferedReader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
}
@Override
protected void onPostExecute(JSONObject response)
{
if(response != null)
{
try {
Log.e("App", "Success: " + response.getString("yourJsonElement") );
} catch (JSONException ex) {
Log.e("App", "Failure", ex);
}
}
}
}
这将是它所针对的json对象。
{
"yourJsonElement":"Hi, I'm a string",
"anotherElement":"Ohh, why didn't you pick me"
}
我正在努力,希望这对其他人有帮助。
答案 2 :(得分:3)
如果您将服务器响应作为字符串获取,而不使用第三方库,则可以执行
-->
编辑没有库(未经测试)
JSONObject json = new JSONObject(response);
JSONObject jsonResponse = json.getJSONObject("response");
String team = jsonResponse.getString("Team");
答案 3 :(得分:2)
在此代码段中,我们将看到一个volley方法,在依赖项内的应用内级别gradle文件中添加
虚拟网址-> https://jsonplaceholder.typicode.com/users(HTTP GET方法请求)
public void getdata(){
Response.Listener<String> response_listener = new Response.Listener<String>() {
@Override
public void onResponse(String response) {
Log.e("Response",response);
try {
JSONArray jsonArray = new JSONArray(response);
JSONObject jsonObject = jsonArray.getJSONObject(0).getJSONObject("address").getJSONObject("geo");
Log.e("lat",jsonObject.getString("lat");
Log.e("lng",jsonObject.getString("lng");
} catch (JSONException e) {
e.printStackTrace();
}
}
};
Response.ErrorListener response_error_listener = new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
if (error instanceof TimeoutError || error instanceof NoConnectionError) {
//TODO
} else if (error instanceof AuthFailureError) {
//TODO
} else if (error instanceof ServerError) {
//TODO
} else if (error instanceof NetworkError) {
//TODO
} else if (error instanceof ParseError) {
//TODO
}
}
};
StringRequest stringRequest = new StringRequest(Request.Method.GET, "https://jsonplaceholder.typicode.com/users",response_listener,response_error_listener);
getRequestQueue().add(stringRequest);
}
public RequestQueue getRequestQueue() {
//requestQueue is used to stack your request and handles your cache.
if (mRequestQueue == null) {
mRequestQueue = Volley.newRequestQueue(getApplicationContext());
}
return mRequestQueue;
}
访问https://github.com/JainaTrivedi/AndroidSnippet-/blob/master/Snippets/VolleyActivity.java
答案 4 :(得分:0)
BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
String sResponse;
StringBuilder s = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
s = s.append(sResponse);
}
Gson gson = new Gson();
JSONObject jsonObject = new JSONObject(s.toString());
String link = jsonObject.getString("Result");
答案 5 :(得分:0)
private class GetProfileRequestAsyncTasks extends AsyncTask<String, Void, JSONObject> {
@Override
protected void onPreExecute() {
}
@Override
protected JSONObject doInBackground(String... urls) {
if (urls.length > 0) {
String url = urls[0];
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
httpget.setHeader("x-li-format", "json");
try {
HttpResponse response = httpClient.execute(httpget);
if (response != null) {
//If status is OK 200
if (response.getStatusLine().getStatusCode() == 200) {
String result = EntityUtils.toString(response.getEntity());
//Convert the string result to a JSON Object
return new JSONObject(result);
}
}
} catch (IOException e) {
} catch (JSONException e) {
}
}
return null;
}
@Override
protected void onPostExecute(JSONObject data) {
if (data != null) {
Log.d(TAG, String.valueOf(data));
}
}
答案 6 :(得分:0)
private class GetProfileRequestAsyncTasks extends AsyncTask<String, Void, JSONObject> {
@Override
protected void onPreExecute() {
}
@Override
protected JSONObject doInBackground(String... urls) {
if (urls.length > 0) {
String url = urls[0];
HttpClient httpClient = new DefaultHttpClient();
HttpGet httpget = new HttpGet(url);
httpget.setHeader("x-li-format", "json");
try {
HttpResponse response = httpClient.execute(httpget);
if (response != null) {
//If status is OK 200
if (response.getStatusLine().getStatusCode() == 200) {
String result = EntityUtils.toString(response.getEntity());
//Convert the string result to a JSON Object
return new JSONObject(result);
}
}
} catch (IOException e) {
} catch (JSONException e) {
}
}
return null;
}
@Override
protected void onPostExecute(JSONObject data) {
if (data != null) {
Log.d(TAG, String.valueOf(data));
}
}
}
答案 7 :(得分:0)
我相当简短的代码,用于从URL读取JSON。 (由于使用CharStreams
,因此需要番石榴)。
private static class VersionTask extends AsyncTask<String, String, String> {
@Override
protected String doInBackground(String... strings) {
String result = null;
URL url;
HttpURLConnection connection = null;
try {
url = new URL("https://api.github.com/repos/user_name/repo_name/releases/latest");
connection = (HttpURLConnection) url.openConnection();
connection.connect();
result = CharStreams.toString(new InputStreamReader(connection.getInputStream(), Charsets.UTF_8));
} catch (IOException e) {
Log.d("VersionTask", Log.getStackTraceString(e));
} finally {
if (connection != null) {
connection.disconnect();
}
}
return result;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
if (result != null) {
String version = "";
try {
version = new JSONObject(result).optString("tag_name").trim();
} catch (JSONException e) {
Log.e("VersionTask", Log.getStackTraceString(e));
}
if (version.startsWith("v")) {
//process version
}
}
}
}
PS:此代码获取给定GitHub存储库的最新发行版(基于标签名称)。
答案 8 :(得分:-1)
不了解android,但在POJ中我使用
public final class MyJSONObject extends JSONObject {
public MyJSONObject(URL url) throws IOException {
super(getServerData(url));
}
static String getServerData(URL url) throws IOException {
HttpURLConnection con = (HttpURLConnection) url.openConnection();
BufferedReader ir = new BufferedReader(new InputStreamReader(con.getInputStream()));
String text = ir.lines().collect(Collectors.joining("\n"));
return (text);
}
}