我有3个li,执行.insertAfter()
后重复内容<ul class="course-list">
<li>
<div class="course-image">
<a href="#"><img src="url_of_photo" /></a>
</div>
<div class="course-content">
<p class="post-title"><a title="" href="/courses/level-2-certificate-in-english/"> Level 2 Certificate In English</a>
</p>
<p class="post-meta post-meta-level">Level 2</p>
<p class="post-meta post-meta-boxcolor">light blue</p>
</div>
</li>
</ul>
我想在class =“course-content”
下面转移class =“course-image”执行时:
$('.course-list .course-image').insertAfter('.course-list .course-content');
结果变为如下:
<ul class="course-list">
<li>
<div class="course-content">
<p class="post-title"><a title="Level 2 Certificate In English For Business" href="/courses/level-2-certificate-in-english/"> Level 2 Certificate In English</a>
</p>
<p class="post-meta post-meta-level">Level 2</p>
<p class="post-meta post-meta-boxcolor">light blue</p>
</div>
<div class="course-image">
<a href="#"><img src="url_of_photo" /></a>
</div>
<div class="course-image">
<a href="#"><img src="url_of_photo" /></a>
</div>
</li>
</ul>
它发生在那个ul的每个人身上。
为每个列表移动class =“course-image”的正确查询是什么,而不必重复evey li?
谢谢!
答案 0 :(得分:3)
你需要迭代并移动
$('.course-list .course-image').each(function(){
$(this).insertAfter($(this).next())
});