Question

我正在尝试使用subinstr()命令删除某些名称中的连字符。不幸的是，没有删除单个连字符和以连字符开头的名称。（有两个原因：＆＃34; -某些东西＆＃34;更具体而不是＆＃34;某些东西＆＃34;，我不想意外删除重要部分一个名字。）

为了取消连字符，我还需要添加额外的东西吗？

代码示例（完整代码在此处添加时间太长）

append using "2011 Death", force;
append using "2012 Death", force;
duplicates drop;
replace ID = subinstr(ID,"HLTH","HEALTH",.);
replace ID = subinstr(ID,"CORPORATION","",.);
replace ID = subinstr(ID,"ASSOCIATIONINC","",.);
replace ID = subinstr(ID,"-P&MED","PITALANDMED",.);
replace ID = subinstr(ID,"-HIGHLANDSMEDICALCENTER","",.);
replace ID = subinstr(ID,"-","",.);
(more along similar lines)

"-highlandmedicalcenter"，"-P&MED"和"-"未被删除，因为处理后仍存在-highlandsmedicalcenter内容的名称。前三个是。我不确定-p$med。

Answer 1

以下使用您的代码的示例适合我。我对您的经验的唯一解释是，您的数据可能包含短划线或短划线而非连字符。

. input str30 s1

                                 s1
  1. "HLTH"
  2. "CORPORATION"
  3. "ASSOCIATIONINC"
  4. "-P&MED"
  5. "-HIGHLANDSMEDICALCENTER"
  6. "-GNXL"
  7. end

. clonevar s2 = s1

. replace s2 = subinstr(s2,"HLTH","HEALTH",.)
(1 real change made)

. replace s2 = subinstr(s2,"CORPORATION","",.)
(1 real change made)

. replace s2 = subinstr(s2,"ASSOCIATIONINC","",.)
(1 real change made)

. replace s2 = subinstr(s2,"-P&MED","PITALANDMED",.)
(1 real change made)

. replace s2 = subinstr(s2,"-HIGHLANDSMEDICALCENTER","",.)
(1 real change made)

. replace s2 = subinstr(s2,"-","",.)
(1 real change made)

. list, clean

                            s1            s2  
  1.                      HLTH        HEALTH  
  2.               CORPORATION                
  3.            ASSOCIATIONINC                
  4.                    -P&MED   PITALANDMED  
  5.   -HIGHLANDSMEDICALCENTER                
  6.                     -GNXL          GNXL  

.

Stata：subinstr没有使用连字符，任何想法

1 个答案: