我正在设置一个程序,该程序会读取用户的输入消息并按字词细分响应。
为了使其适应,我需要将由one million
,35 million
,230 thousand
等字符串描述的数字转换回1000000
,{{ 1}},35000000
。
我尝试了一些方法,但找不到有效方法。
例如用户帖子20000
:
one million
答案 0 :(得分:0)
检查Converting words to numbers in PHP:
/**
* Convert a string such as "one hundred thousand" to 100000.00.
*
* @param string $data The numeric string.
*
* @return float or false on error
*/
function wordsToNumber($data) {
// Replace all number words with an equivalent numeric value
$data = strtr(
$data,
array(
'zero' => '0',
'a' => '1',
'one' => '1',
'two' => '2',
'three' => '3',
'four' => '4',
'five' => '5',
'six' => '6',
'seven' => '7',
'eight' => '8',
'nine' => '9',
'ten' => '10',
'eleven' => '11',
'twelve' => '12',
'thirteen' => '13',
'fourteen' => '14',
'fifteen' => '15',
'sixteen' => '16',
'seventeen' => '17',
'eighteen' => '18',
'nineteen' => '19',
'twenty' => '20',
'thirty' => '30',
'forty' => '40',
'fourty' => '40', // common misspelling
'fifty' => '50',
'sixty' => '60',
'seventy' => '70',
'eighty' => '80',
'ninety' => '90',
'hundred' => '100',
'thousand' => '1000',
'million' => '1000000',
'billion' => '1000000000',
'and' => '',
)
);
// Coerce all tokens to numbers
$parts = array_map(
function ($val) {
return floatval($val);
},
preg_split('/[\s-]+/', $data)
);
$stack = new SplStack; // Current work stack
$sum = 0; // Running total
$last = null;
foreach ($parts as $part) {
if (!$stack->isEmpty()) {
// We're part way through a phrase
if ($stack->top() > $part) {
// Decreasing step, e.g. from hundreds to ones
if ($last >= 1000) {
// If we drop from more than 1000 then we've finished the phrase
$sum += $stack->pop();
// This is the first element of a new phrase
$stack->push($part);
} else {
// Drop down from less than 1000, just addition
// e.g. "seventy one" -> "70 1" -> "70 + 1"
$stack->push($stack->pop() + $part);
}
} else {
// Increasing step, e.g ones to hundreds
$stack->push($stack->pop() * $part);
}
} else {
// This is the first element of a new phrase
$stack->push($part);
}
// Store the last processed part
$last = $part;
}
return $sum + $stack->pop();
}