我希望在查询后获得两条记录之间的区别。
这是查询:
select count(t.customerid) as NumberofCustomers, st.regionid, v.vendorid
from region r join store st
on r.regionid = st.regionid
join salestransaction t
on st.storeid = t.storeid
join soldvia s
on t.tid = s.tid
join product p
on s.productid = p.productid
join vendor v
on p.vendorid = v.vendorid
where v.vendorid = 2
group by st.regionid, v.vendorid
这是查询产生的内容:
NumberofCustomers regionid vendorid
495 1 2
329 2 2
我怎样才能得到row1和row2中NumberofCustomers之间的区别? 我试图使用差异实现这一点,但它没有给我想要的结果。
任何帮助将不胜感激。
答案 0 :(得分:0)
你的目标很奇怪。但是我有一个有趣而奇怪的解决方案:
SELECT t.*,
IF(@prev IS NULL, t.NumberofCustomers, (t.NumberofCustomers- @prev)) difference,
@prev := t.NumberofCustomers
FROM )
select count(t.customerid) as NumberofCustomers,
st.regionid, v.vendorid
from region r join store st
on r.regionid = st.regionid
join salestransaction t
on st.storeid = t.storeid
join soldvia s
on t.tid = s.tid
join product p
on s.productid = p.productid
join vendor v
on p.vendorid = v.vendorid
where v.vendorid = 2
group by st.regionid, v.vendorid ) t
答案 1 :(得分:0)
如果您只有两个区域,则可以使用条件聚合:
select v.vendorid,
sum(st.regionid = 1) as NumRegion1,
sum(st.regionid = 2) as NumRegion2,
(sum(st.regionid = 1) - sum(st.regionid = 2)) as diff
from region r join
store st
on r.regionid = st.regionid join
salestransaction t
on st.storeid = t.storeid join
soldvia s
on t.tid = s.tid join
product p
on s.productid = p.productid join
vendor v
on p.vendorid = v.vendorid
where v.vendorid = 2
group by v.vendorid;
将数字全部返回一行,而不是两行。